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Article

Uniqueness of Single Peak Solutions for a Kirchhoff Equation

1
School of Science, Jiangsu University of Science and Technology, Zhenjiang 212003, China
2
Yangzijiang Shipbuilding Group, Taizhou 212299, China
*
Author to whom correspondence should be addressed.
Mathematics 2024, 12(10), 1462; https://doi.org/10.3390/math12101462
Submission received: 29 March 2024 / Revised: 29 April 2024 / Accepted: 6 May 2024 / Published: 8 May 2024
(This article belongs to the Section Difference and Differential Equations)

Abstract

:
We deal with the following singular perturbation Kirchhoff equation: ϵ 2 a + ϵ b R 3 | u | 2 d y Δ u + Q ( y ) u = | u | p 1 u , u H 1 ( R 3 ) , where constants a , b , ϵ > 0 and 1 < p < 5 . In this paper, we prove the uniqueness of the concentrated solutions under some suitable assumptions on asymptotic behaviors of Q ( y ) and its first derivatives by using a type of Pohozaev identity for a small enough ϵ . To some extent, our result exhibits a new phenomenon for a kind of Q ( x ) which allows for different orders in different directions.
MSC:
35A01; 35A02; 35B25; 35J20; 35J60

1. Introduction

In 1746, D’Alembert first formulated the wave equation in his treatise and proved its functional relationships in 1750. The study of elastic string vibrations pioneered the discipline of partial differential equations. In 1883, Kirchhoff [1] extended the classical D’Alembert wave equation to the free vibration of elastic strings by considering a physical model for the change in string length due to transverse vibrations.
ρ 2 u t 2 P 0 h + E 2 L 0 L | 2 u y 2 | d y 2 u y 2 = 0 ,
where L is the length of the string, h is the cross-sectional area, E is the Young’s modulus of the material, ρ is the mass density, and P 0 is the initial tension. With further research, scholars have found that Kirchhoff-type equations have a wealth of applications [2,3,4] and have become a typical class of issues in partial differential equations.
In this paper, we are concerned with the following nonlocal Kirchhoff problem
ϵ 2 a + ϵ b R 3 | u | 2 d y Δ u + Q ( y ) u = | u | p 1 u , u H 1 ( R 3 ) ,
where ϵ > 0 is a small parameter, and constants a , b > 0 and 1 < p < 5 .
In recent decades, there has been considerable interest in the existence and uniqueness of solutions for (2) under suitable conditions on the function Q ( y ) . In particular, when ϵ = 1 and Q ( y ) is a constant, the existence and non-degeneracy of ground state solutions were implied in [5,6]. Using the non-degeneracy of ground states, in [5], Li et al. added the existence and uniqueness of single-peak solutions to (2) and Luo, Peng, Wang and Xiang [7] obtained the existence of multi-peak positive solutions of (2) by combining the variational method and the Lyapunov–Schmidt reduction for small ϵ . For more works concerning the uniqueness of concentrated solutions, one can refer to [8,9,10,11,12].
Now, we state the conditions of Q ( y ) in [5] as follows:
( Q 1 )  Q ( y ) is a bounded C 1 function with inf y R 3 Q ( y ) > 0 .
( Q 2 ) There exist y 0 R 3 and r 0 > 0 such that Q ( y 0 ) < Q ( y ) for 0 < | y y 0 | < r 0 .
( Q 3 ) There exist m > 1 and ρ > 0 such that
Q ( y ) = Q ( y 0 ) + j = 1 3 c j | y j y j 0 | m + O ( | y y 0 | m + 1 ) , y B ρ ( y 0 ) , Q ( y ) y j = m c j | y j y j 0 | m 2 ( y j y j 0 ) + O ( | y y 0 | m ) , y B ρ ( y 0 ) ,
where ρ > 0 is a small constant and c j 0 for j = 1 , 2 , 3 .
Theorem 1
(c.f. [5]). Suppose that Q ( y ) satisfies ( Q 1 ) , ( Q 2 ) and ( Q 3 ) . Let u ϵ ( i ) , i = 1 , 2 be two positive solutions of (2) concentrating at the same point y 0 . Then, u ϵ ( 1 ) = u ϵ ( 2 ) for a sufficiently small ϵ.
Here, we want to mention that the authors in [5] used the assumption that Q ( y ) has the same order in different directions at y 0 . However, to our knowledge, whether there is similar uniqueness when Q ( y ) has different increasing rates in different directions is still unknown. In this paper, we give an answer on this aspect and we consider a class of Q ( y ) as follows:
( Q ¯ 3 )  Q ( y 0 ) < Q ( y ) for any y R 3 { y 0 } and Q ( y ) satisfies
Q ( y ) = Q ( y 0 ) + j = 1 3 c j | y j y j 0 | m j + O ( | y y 0 | m + 1 ) , y B ρ ( y 0 ) , Q ( y ) y j = m c j | y j y j 0 | m j 2 ( y j y j 0 ) + O ( | y y 0 | m ) , y B ρ ( y 0 ) ,
where ρ > 0 is a small constant, m j > 1 , m = max { m 1 , m 2 , m 3 } and c j 0 for j = 1 , 2 , 3 .
Theorem 2.
Suppose that Q ( y ) satisfies ( Q 1 ) and ( Q ¯ 3 ) . Then, (2) has only one positive single-peak solution if ϵ is small enough.

2. Some Basic Estimates

Let U y 0 ( y ) be the unique positive solution of the following problem:
a + b R 3 | u | 2 d y Δ u + Q ( y 0 ) u = | u | p 1 u , i n R 3 , u ( 0 ) = max y R 3 u ( y ) , u ( y ) H 1 ( R 3 ) .
It follows from [5] that U y 0 ( y ) is a radially symmetric decreasing function satisfying
| D α U y 0 ( y ) | C e δ | y | , with | α | 1 and   some C , δ > 0 .
First we denote
u ϵ = ( u ( y ) , u ( y ) ) ϵ 1 2 = R 3 ( ϵ 2 a | u | 2 + Q ( y ) u 2 ( y ) ) 1 2 ,
and for x R 3 , we let
E ϵ , x = u H 1 ( R 3 ) : ( u ( y ) , U y 0 ( y x ϵ ) ) ϵ = 0 , ( u ( y ) , U y 0 ( y x ϵ ) y j ) ϵ = 0 , j = 1 , 2 , 3 .
By using the standard Lyapunov–Schmidt reduction as that in Theorem 1.3 in [5], the following basic structure of the concentrated solutions can be obtained.
Proposition 1.
Suppose that Q ( y ) satisfies ( Q 1 ) and ( Q ¯ 3 ) . Then, there exists ϵ 0 such that for all ϵ ( 0 , ϵ 0 ) , problem (2) has a solution u ϵ of the form
u ϵ ( y ) = U y 0 ( y y ϵ ϵ ) + ω ϵ ( y ) ,
with y ϵ , ω ϵ E ϵ , y ϵ satisfying
| y ϵ y 0 | = o ( 1 ) , ω ϵ ϵ = o ( ϵ 3 2 ) .
Now, we consider
L ϵ ( ω ϵ ) = ϵ 2 a + ϵ b R 3 | U y 0 ( y y ϵ ϵ ) | 2 Δ ω ϵ + 2 ϵ b R 3 U y 0 ( y y ϵ ϵ ) ω ϵ Δ U y 0 ( y y ϵ ϵ ) + Q ( y ) ω ϵ p U y 0 p 1 ( y y ϵ ϵ ) ω ϵ .
We can rewrite L ϵ ( ω ϵ ) as
L ϵ ( ω ϵ ) = R ϵ ( ω ϵ ) + N ϵ ( ω ϵ ) ,
where R ϵ ( ω ϵ ) = ( Q ( y 0 ) Q ( y ) ) U y 0 ( y y ϵ ϵ ) , and
N ϵ ( ω ϵ ) = { 2 ϵ b R 3 U y 0 ( y y ϵ ϵ ) ω ϵ Δ U y 0 ( y y ϵ ϵ ) + ϵ b R 3 2 U y 0 ( y y ϵ ϵ ) ω ϵ + | ω ϵ | 2 Δ ( U y 0 ( y y ϵ ϵ ) + ω ϵ ) } + { U y 0 ( y y ϵ ϵ ) + ω ϵ p U y 0 p ( y y ϵ ϵ ) p U y 0 p 1 ( y y ϵ ϵ ) ω ϵ } = : N ϵ 2 ( ω ϵ ) + N ϵ 1 ( ω ϵ ) .
Lemma 1
(c.f. [5]). There exist ϵ 1 > 0 , ρ 1 > 0 and γ > 0 sufficiently small such that for any ϵ ( 0 , ϵ 1 ) , ρ ( 0 , ρ 1 ) ,
| R 3 L ϵ ( ω ϵ ) ω ϵ | γ ω ϵ ϵ 2
holds uniformly with respect to y ϵ B ρ ( y 0 ) .
Proposition 2.
It holds
ω ϵ ϵ = O ( ϵ 3 2 + min { m 1 , m 2 , m 3 } ) + O ( ϵ 3 2 max j = 1 , 2 , 3 | y ϵ , j y j 0 | m j ) .
Proof. 
First, using the condition ( Q ¯ 3 ) and the Hölder inequality, for a small constant d, we have
| B d ( y ϵ ) R ϵ ( ω ϵ ) ω ϵ | = | B d ( y ϵ ) ( Q ( y 0 ) Q ( y ) ) U y 0 ( y y ϵ ϵ ) ω ϵ | C j = 1 3 B d ( y ϵ ) | y j y j 0 | m j U y 0 ( y y ϵ ϵ ) | ω ϵ | C ϵ 3 2 j = 1 3 ( ϵ m j + | y ϵ , j y j 0 | m j ) | | ω ϵ | | ϵ ,
where y j , y ϵ , j , y j 0 denote the jth components of y , y ϵ , y 0 .
Moreover, by the exponential decay of U y 0 ( y y ϵ ϵ ) , we can obtain that for any σ > 0 ,
| R 3 B d ( y ϵ ) R ϵ ( ω ϵ ) ω ϵ | C ϵ σ | | ω ϵ | | ϵ .
Thus, (6) and (7) give that
| R 3 R ϵ ( ω ϵ ) ω ϵ | = O ( ϵ 3 2 + min { m 1 , m 2 , m 3 } ) | | ω ϵ | | ϵ + O ( ϵ 3 2 max j = 1 , 2 , 3 | y ϵ , j y j 0 | m j ) | | ω ϵ | | ϵ .
On the other hand, it can be directly calculated that
| R 3 N ϵ 1 ( ω ϵ ) ω ϵ | C R 3 | ω ϵ ( y ) | min { p + 1 , 3 } = o ( 1 ) | | ω ϵ | | ϵ 2 ,
| B d ( y ϵ ) N ϵ 2 ( ω ϵ ) ω ϵ | = | 3 ϵ b R 3 U y 0 ( y y ϵ ϵ ) ω ϵ ( y ) R 3 | ω ϵ | 2 ϵ b R 3 | ω ϵ | 2 4 | = o ( 1 ) | | ω ϵ | | ϵ 2 .
So, from (5), (8)–(10) and Lemma 1, the result follows. □
Proposition 3.
Suppose that u ϵ ( y ) is a positive solution of (2). Then, for any R > > 1 , there exist η > 0 and C > 0 such that
| u ϵ ( y ) | + | u ϵ ( y ) | C e η | y y ϵ | ϵ , x R 3 B R ϵ ( y ϵ ) .
Proof. 
Using the comparison principle of He and Xiang [13], we can obtain (11), which also can be found in [5]. □
Let u ( y ) be a positive solution of (2). Then, by multiplying y j u on both sides of (2) and then integrating by parts, we have for each j = 1 , 2 , 3
R 3 Q y j u 2 ( y ) d y = 0 .
Proposition 4.
Let u ϵ ( y ) be the solution of (2) with the form (3) and (4). Assume that ( Q 1 ) and ( Q ¯ 3 ) hold. Then,
ω ϵ ϵ = O ( ϵ 3 2 + min { m 1 , m 2 , m 3 } ) and | y ϵ y 0 | = o ( ϵ ) .
Proof. 
First, (11) and (12) tell us that for a small d > 0 , there exists some σ > 0 such that
B d ( y ϵ ) Q y j U y 0 ( y y ϵ ϵ ) + ω ϵ 2 d y = O ( e σ ϵ ) .
Also, similar to (6), we have
| B d ( y ϵ ) Q y j U y 0 ( y y ϵ ϵ ) ω ϵ d y | C ϵ 3 2 ( ϵ m j 1 + | y ϵ , j y j 0 | m j 1 ) | | ω ϵ | | ϵ ,
which implies that from Proposition 2
| B d ( y ϵ ) Q y j U y 0 2 ( y y ϵ ϵ ) d y | = O ( ϵ 3 ( ϵ m j + min { m 1 , m 2 , m 3 } 1 + max j = 1 , 2 , 3 | y ϵ , j y j 0 | 2 m j 1 ) ) .
On the other hand, we also find
LHS of ( 13 ) = c j m j ϵ 3 B d ϵ ( 0 ) | ϵ y j + y ϵ , j y j 0 | m j 2 ( ϵ y j + y ϵ , j y j 0 ) U y 0 2 ( y ) d y + O ( ϵ 3 ( ϵ m + | y ϵ y 0 | m ) ) .
Thus, (13) and (14) imply that
B d ϵ ( 0 ) | y j + y ϵ , j y j 0 ϵ | m j 2 ( y j + y ϵ , j y j 0 ϵ ) U y 0 2 ( y ) d y = O ( ϵ ) + O ( ϵ m j 1 ) ,
which, together with Proposition 2, gives that for j = 1 , 2 , 3 ,
| y ϵ , j y j 0 | = O ( ϵ ) and ω ϵ ϵ = O ( ϵ 3 2 + min { m 1 , m 2 , m 3 } ) .
Up to a subsequence, we can suppose that | y ϵ , j y j 0 | ϵ y ˜ . Then, letting ϵ 0 in (15), we have
R 3 | y j + y ˜ j | m j 2 ( y j + y ˜ j ) U y 0 2 ( y ) d y = 0 .
This gives that y ˜ = 0 since U y 0 ( | y | ) is strictly decreasing with respect to | y | . So, | y ϵ y 0 | = o ( ϵ ) . □

3. Proof of the Main Theorem

Suppose that u ϵ ( j ) , j = 1 , 2 are two distinct solutions derived as in Proposition 1. By (11), u ϵ ( j ) , j = 1 , 2 are bounded functions in R 3 . Set
η ϵ = u ϵ ( 1 ) u ϵ ( 2 ) u ϵ 1 u ϵ 2 L ( R 3 ) .
Then, η ϵ L ( R 3 ) = 1 , and similar to Propositions 6.1 and 6.2 in [5], we have
Lemma 2.
There holds
η ϵ ϵ = O ( ϵ 3 2 ) .
Lemma 3.
Letting η ¯ ϵ = η ϵ ( ϵ y + y ϵ ( 1 ) ) , then there exist β j R , j = 1 , 2 , 3 such that, up to a subsequence if necessary, η ¯ ϵ ( y ) j = 1 3 β j U y 0 ( y ) y j uniformly in C 1 B R ( 0 ) for any R > 0 .
Lemma 4.
Let β j be as in Lemma 3. Then, β j = 0 , f o r j = 1 , 2 , 3 .
Proof. 
Since u ϵ ( 1 ) , u ϵ ( 2 ) are the positive solutions of (2), the Pohazaev identity (12) gives that
B d ( y ϵ 1 ) Q y j ( u ϵ ( 1 ) ( y ) + u ϵ ( 2 ) ( y ) ) η ϵ ( y ) d y = O ( e σ ϵ ) .
On the other hand,
B d ( y ϵ ( 1 ) ) Q y j ( u ϵ ( 1 ) ( y ) + u ϵ ( 2 ) ( y ) ) η ϵ ( y ) d y = m j c j B d ( y ϵ ( 1 ) ) | y j y j 0 | m j 2 ( y j y j 0 ) ( u ϵ ( 1 ) ( y ) + u ϵ ( 2 ) ( y ) ) η ϵ ( y ) d y + O B d ( y ϵ ( 1 ) ) | y y 0 | m ( u ϵ ( 1 ) ( y ) + u ϵ ( 2 ) ( y ) ) η ϵ ( y ) d y .
Note that
u ϵ ( 1 ) ( y ) + u ϵ ( 2 ) ( y ) = 2 U y 0 y y ϵ ( 1 ) ϵ + o ( 1 ) U y 0 y y ϵ ( 1 ) ϵ + O j = 1 2 | ω ϵ ( j ) | .
Then, it holds
B d ( y ϵ ( 1 ) ) | y j y j 0 | m j 2 ( y j y j 0 ) ( u ϵ ( 1 ) ( y ) + u ϵ ( 2 ) ( y ) ) η ϵ ( y ) d y = 2 B d ( y ϵ ( 1 ) ) | y j y j 0 | m j 2 ( y j y j 0 ) U y 0 y y ϵ ( 1 ) ϵ η ϵ ( y ) d y + o ( 1 ) B d ( y ϵ ( 1 ) ) | y j y j 0 | m j 2 ( y j y j 0 ) U y 0 y y ϵ ( 1 ) ϵ η ϵ ( y ) d y + O B d ( y ϵ 1 ) | y j y j 0 | m j 1 ( | ω ϵ ( 1 ) ( y ) | + | ω ϵ ( 2 ) ( y ) | ) η ϵ ( y ) d y .
Now, since U y 0 ( y ) y j is an odd function with respect to y j and an even function with respect to y i for i j , using Lemma 3, we deduce that
B d ( y ϵ ( 1 ) ) | y j y j 0 | m j 2 ( y j y j 0 ) U y 0 y y ϵ ( 1 ) ϵ η ϵ ( y ) d y = ϵ m j + 2 B d ϵ ( 0 ) | y j + y ϵ , j ( 1 ) y j 0 ϵ | m j 2 ( y j + y ϵ , j ( 1 ) y j 0 ϵ ) U y 0 ( y ) j = 1 3 β j U y 0 ( y ) y j + o ( 1 ) d y = β j ϵ m j + 2 R 3 | y j | m j 2 y j U y 0 ( y ) U y 0 ( y ) y j d y + o ( ϵ m j + 2 ) ,
and similarly,
B d ( y ϵ ( 1 ) ) | y j y j 0 | m j 2 ( y j y j 0 ) U y 0 y y ϵ ( 1 ) ϵ η ϵ ( y ) d y = O ( ϵ m j + 2 ) .
Also, Proposition 4 gives that
B d ( y ϵ ( 1 ) ) | y j y j 0 | m j 1 ( | ω ϵ ( 1 ) ( y ) | + | ω ϵ ( 2 ) ( y ) | ) η ϵ ( y ) d y = O ( ϵ m j 1 ( ω ϵ ( 1 ) ϵ + ω ϵ ( 2 ) ϵ ) η ϵ ϵ ) = O ( ϵ m j + 2 + min { m 1 , m 2 , m 3 } ) .
Moreover, with the same argument, we obtain
B d ( y ϵ ( 1 ) ) | y y 0 | m ( u ϵ ( 1 ) ( y ) + u ϵ ( 2 ) ( y ) ) η ϵ ( y ) d y = O ( ϵ m + 3 ) .
Then, from (20)–(24), it holds
LHS of ( 18 ) = 2 c j m j β j ϵ m j + 2 R 3 | y j | m j 2 y j U y 0 ( y ) U y 0 ( y ) y j d y + o ( ϵ m j + 2 ) .
Thus, (17) and (25) imply that β j = 0 . □
Proof of Theorem 2.
Suppose that u ϵ ( j ) , j = 1 , 2 are two distinct solutions derived as in Proposition 1; then, η ϵ L ( R 3 ) = 1 by assumption. But it follows from Lemmas 3 and 4 and the maximum principle that η ϵ ( y ) = 0 . We reach a contradiction by constructing η ϵ . We find u ϵ ( 1 ) = u ϵ ( 1 ) , which proves that problem (2) has only one positive single-peak solution if ϵ is small enough. □

Author Contributions

Methodology, S.Y.; Formal analysis, B.S.; Writing—original draft, J.L. All authors have read and agreed to the published version of the manuscript.

Funding

This research received no external funding.

Data Availability Statement

The data will be made available by the authors on request.

Conflicts of Interest

Shichao Yi was employed by Yangzijiang Shipbuilding Group. The remaining authors declare that the research was conducted in the absence of any commercial or financial relationships that could be construed as a potential conflict of interest. The Yangzijiang Shipbuilding Group had no role in the design of the study; in the collection, analyses, or interpretation of data; in the writing of the manuscript, or in the decision to publish the results.

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Lv, J.; Yi, S.; Sun, B. Uniqueness of Single Peak Solutions for a Kirchhoff Equation. Mathematics 2024, 12, 1462. https://doi.org/10.3390/math12101462

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Lv J, Yi S, Sun B. Uniqueness of Single Peak Solutions for a Kirchhoff Equation. Mathematics. 2024; 12(10):1462. https://doi.org/10.3390/math12101462

Chicago/Turabian Style

Lv, Junhao, Shichao Yi, and Bo Sun. 2024. "Uniqueness of Single Peak Solutions for a Kirchhoff Equation" Mathematics 12, no. 10: 1462. https://doi.org/10.3390/math12101462

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