1. Introduction
The Arzelà–Ascoli theorem is an important result of mathematical analysis. It deals with compactness in the space of real-valued continuous functions on a compact space. The notion of equicontinuity is a key notion in this theorem. It was introduced by the Italian mathematicians Cesare Arzelà [
1,
2] and Giulio Ascoli [
3].
If
X is a locally compact space and
is a metric space, a subset
of
of continuous functions from
X to
Y is compact in
if and only if
is closed in
,
is equicontinuous and the closure of the set
is compact in
Y for every
[
4]. The set
is equicontinuous if for each
and every
there is a neighborhood
G of
x with
for every
and every
.
We say that a function
f between metric spaces
X and
Y is Baire 1 if the preimage of any open set is
(cf. [
5] [Def. 24.1]). Such functions are also called in the literature
-measurable functions. The notion of the Baire 1 function is a classical one. In 1905, Lebesgue [
6] characterized Baire 1 functions with values in
. A detailed study of classical results concerning Baire 1 functions from a metric space into a separable metric space can be found in [
7]. In the literature, we can find several characterizations of Baire 1 functions; see [
5] [Thm 24.15]. Recently, a new characterization of Baire 1 functions was proved in [
8] and [
9]. It is known that if
, the Baire 1 function is a limit of a pointwise convergent sequence of continuous functions. There is rich literature concerning Baire 1 functions; see [
8,
9,
10,
11,
12,
13,
14] and others.
In our paper, we prove Ascoli-type theorem for locally bounded Baire 1 functions using a special form of equi-Lebesgue family. The notion of equi-Lebesgue family of functions from
X to
Y was introduced in [
14], and it also appeared in [
10] and in [
11]. If
X is a separable metric space, then the notion of equi-Lebesgue family coincides with the notion of equi-Baire 1 family introduced by Lecomte in his paper [
10]. Lecomte studied versions of Ascoli’s theorem for Baire 1 functions. He also proved the following result. Let
X be a locally compact separable metric space,
Y be a separable metric space,
be the space of Baire 1 functions from
X to
Y, and
be the topology of uniform convergence on compacta. If
, equipped with
, is relatively compact in
, then
is equi-Baire 1. Lecomte did not prove in [
10] a characterization of compact subsets of
equipped with the topology of uniform convergence on compacta.
In [
15], Ascoli-type theorem for quasicontinuous locally bounded functions was studied, and in [
16], Ascoli-type theorems for quasicontinuous subcontinuous functions were proved. In [
17], the authors studied compact subsets of quasicontinuous functions, and in [
18], they studied compact subsets of minimal usco and minimal cusco maps equipped with the topology of uniform convergence on compact sets. Ascoli-type theorems for so-called densely continuous forms and locally bounded densely continuous forms were proved in [
19,
20]. Notice that minimal usco/cusco maps and densely continuous forms are set-valued mappings, and the class of quasicontinuous mappings is entirely different from the class of Baire 1 functions. There are easy examples of Baire 1 functions that are not quasicontinuous, and also, there are quasicontinuous functions from
to
that are not Lebesgue-measurable [
21]. The mentioned papers cannot be used for characterization of compact subsets in
. In [
22], the authors studied Ascoli-type theorem for locally bounded functions. Some results concerning the compactness of locally bounded Baire 1 functions can be found in [
22]; however, they are only for
X, which is compact, and
Y, which is boundedly compact.
The paper is organized as follows. In
Section 2, we recall a characterization of Baire 1 functions between metric spaces
X and
Y, which will be important for our study. In
Section 3, we study metrizability and complete metrizability of
. In
Section 4, necessary conditions for compact subsets of
are given. In
Section 5, we prove Ascoli-type theorem for locally bounded Baire 1 functions with values in metric spaces in which every bounded set is totally bounded. In
Section 6, we present our opinion on the importance of our paper.
2. Preliminaries
In our paper, we denote the space of real numbers with the usual Euclidean metric and the set of positive integers.
Let be a metric space. Denote by the open d-ball with center and radius and by the -parallel body for a subset A. The closure of will be denoted by .
Let
X be a topological space,
be the family of all compact subsets of
X, and
be a metric space. The topology
of uniform convergence on compacta on
is induced by the uniformity
of uniform convergence on compacta, which has a base consisting of sets of the form
where
and
.
Denote by
the
-basic neighborhood of
. Thus,
Denote by the topology of pointwise convergence on .
The following theorem was proved in [
7].
Theorem 1. Let be a metric space and be a separable metric space. A function is Baire 1 if and only if for every there is a countable family such that is a closed set for every , and for every .
We will need the following result from [
14].
Remark 1. Let and be metric spaces and . If for every there is a countable family such that is a closed set for every , and for every , then g is Baire 1.
In [
5] [Thm 24.14], it was proved that if
,
are metric spaces,
is separable, and
is Baire 1, then the set of points of discontinuity of
g is a
set of the first Baire category. We will improve this result.
We say that a collection
of nonempty open subsets of a topological space
X is a pseudo-base [
23] for
X if, for every nonempty open subset
U of
X, there is
such that
.
The following result will be useful.
Lemma 1 ([
24]).
Let X be a topological space. The following are equivalent:(1) A set M is of the first Baire category in X;
(2) There is a pseudo-base for X such that for every , is of the first Baire category in H.
Proposition 1. Let , be metric spaces and be Baire 1. Suppose that there is a dense set D in X such that for every , there is a neighborhood O of x with separable. Then, the set of points of discontinuity of g is a set of the first Baire category.
Proof. Put
is not continuous at
. Since the set of points of discontinuity of
g has to be a
set, it is sufficient to prove that
M is of the first Baire category. Put
open and
is of the first Baire category in
. We will prove that
is a pseudo-base for
X. Let
U be a nonempty open set in
X. Let
. There is an open set
such that
and
is a separable subset of
Y. The function
satisfies conditions of Theorem 24.14 in [
5]. Thus,
is not continuous at
is of the first Baire category in
O. Since the set
is not continuous at
is equal to the set
is not continuous at
, the set
is of the first Baire category in
O. Then,
and
. Thus,
is a pseudo-base for
X. By Lemma 1, the set
M is of the first Baire category in
X. □
Corollary 1. Let be a Baire metric space, be a metric space, and be Baire 1. Suppose there is a dense set D in X such that for every , there is a neighborhood O of x with separable. Then, the set of points of continuity of g is a dense set in X.
Proof. In every Baire space, the complement of a set of the first Baire category is a dense set. □
3. Metrizability of
A topological space
X is hemicompact [
25] if there is a countable family
of compact sets in
X such that for every
there is
with
. Every hemicompact metric space is locally compact [
25]; however,
-compact metric space need not be hemicompact.
Thus, if
is a hemicompact metric space, then it is locally compact and separable. Also, if
is a locally compact separable metric space, then it is a hemicompact metric space. It is also known that if
is a locally compact separable metric space, then there is a compatible metric
on
X such that every closed
-bounded set is compact [
26]. Such spaces are called boundedly compact metric spaces [
27].
In what follows, let and be metric spaces with at least two different points and be the family of Baire 1 functions from X to Y.
Lemma 2. Let and be metric spaces. If X is hemicompact, then the uniformity on is induced by a metric. Thus also the uniformity on is induced by a metric and is metrizable.
Proof. Let
be a countable family in
such that for every
there is
with
. Then, the family
is a countable base of
. By the metrization theorem in [
4], the uniformity
on
is induced by a metric, and thus,
on
is also induced by a metric. □
Using a similar idea as in ([
21], Theorem 2.8.1), it can be shown that
is metrizable if and only if the space
X is hemicompact.
The pointwise limit of a sequence of Baire 1 functions need not be Baire 1. A uniform limit of a sequence of Baire 1 functions is Baire 1 [
7]. We also have the following proposition.
Proposition 2. Let be a σ-compact metric space and be a metric space. Let be a sequence of Baire 1 functions from X to Y, which converges uniformly on compact sets to a function f from X to Y. Then f is a Baire 1 function.
Proof. Let
. Then, the sequence
converges uniformly to
. For every
, the function
belongs to
[
7] [p. 386]. Thus, by [
7] [p. 395], the function
also belongs to
.
Let
be a countable subfamily in
such that
. Since
for every
, by ([
7], p. 385)
. □
Corollary 2. Let be a hemicompact metric space and be a metric space. is a closed set in .
Proof. If is a hemicompact metric space, then by Lemma 2, is a metrizable space. If is in the closure of in , then there is a sequence of Baire 1 functions from X to Y, which converges to f uniformly on compact sets. By Proposition 2. □
Corollary 3. Let be a hemicompact metric space and be a complete metric space. Then, is a completely metrizable space.
Proof. If
is a complete metric space, then by [
4],
is a complete uniform space. By Lemma 2, the uniformity
on
is induced by a metric. By Corollary 2,
is a closed set in
. □
If
is a hemicompact metric space, then using any countable cofinal subfamily in
, we can define a natural metric on
, which induces
and thus also on
[
21].
4. Necessary Conditions for Compact Subsets of
Lee, Thang, and Zhao, in their paper [
8], found an interesting characterization of Baire 1 functions between Polish spaces. Fenecios and Cabral in [
9] proved the following theorem.
Theorem 2 ([
9]).
Let and be separable metric spaces. A function is Baire 1 if and only if for every there exists a function such that for every and if , then . In his paper [
10], Lecomte introduced the notion of equi-Baire 1 family of functions.
Definition 1 ([
10]).
Let and be metric spaces. A family of functions from X to Y is equi-Baire 1 if, for each , there is a function such that for every and implies for every . Notice that the notion of equi-Baire 1 family of functions can also be found in the paper of Alighani-Koopaei [
11], who showed its applications in dynamical systems [
11,
12].
In [
14], the authors introduced the notion of equi-Lebesgue family.
Definition 2. Let and be metric spaces. A family of functions from X to Y is called equi-Lebesgue if, for every , there is a countable family such that is a closed set for every , and for every and for every .
Notice that every member of an equi-Lebesgue family of functions from X to Y is a Baire 1 function (see Remark 1).
It can be observed from the proof of Theorem 3.6 in [
11] that every equi-Lebesgue family of functions from a metric space
X to a metric space
Y is equi-Baire 1, and if
X is separable, then the notions of equi-Lebesgue and equi-Baire 1 families of functions from
X to
Y coincide.
Lecomte, in his paper [
10], proved the following result.
Proposition 3. Let be a locally compact separable metric space and be a separable metric space. If , equipped with the topology of uniform convergence on compacta, is relatively compact in , then is equi-Baire 1.
We have the following generalization of Proposition 3 with a different proof.
Proposition 4. Let be a locally compact separable metric space and be a separable metric space. Let be a totally bounded set in . Then, is the equi-Lebesgue family, and thus is also equi-Baire 1.
Proof. Of course,
is hemicompact. Let
be a countable cofinal subfamily in
. Let
and
. Since
is totally bounded in
, there are functions
such that
Let be a countable family of open sets in Y, such that for every and .
For each
and
, put
Since
is a Baire 1 function, the set
is a
set for every
,
. Put
Every set is a set. Let be the family containing all nonempty sets from . Clearly, and the family is countable. Then for every and for every , .
Since , we are done. □
Corollary 4. Let be a hemicompact metric space and be a separable metric space. If is a compact set in , then is a closed set in , is the equi-Lebesgue family, and is compact in for every .
Lecomte in his paper [
10] presented metric spaces
,
and the equi-Baire 1 family
, such that
is closed in
,
is compact in
for every
and
is not compact in
.
For the reader’s convenience, we present an easier example.
Example 1. Let equipped with the usual Euclidean metric. Let be a sequence of different points in that converges to a point . Put . Then, A is a compact set in ; thus, the complement of A is an set in . Put . It is easy to verify that is equi-Lebesgue family. Put , where is a closed set for every . Then, the family is a countable cover of closed sets, such that for every , every and every . Of course, is compact for every , is a closed set in , and is not compact, since the sequence has no cluster point in .
5. Ascoli-Type Theorem for Locally Bounded Baire 1 Functions
Definition 3. Let and be metric spaces. A subset of is finitely equi-Lebesgue at if, for every , there is a finite family of nonempty subsets of X that are either open or nowhere dense such that is a neighborhood of and such that for every , for every , . is finitely equi-Lebesgue provided that it is finitely equi-Lebesgue at every point of X.
Remark 2. If is a hemicompact metric space, then every finitely equi-Lebesgue subfamily of is equi-Lebesgue.
Notice that in the study of Ascoli-type theorem for quasicontinuous functions in [
15,
16,
21], the notion of a densely equiquasicontinuous family of functions was used.
Proposition 5. Let and be metric spaces. Let be a finitely equi-Lebesgue family of functions from X to Y. Then, the topologies and coincide on .
Proof. Let
be a net in
which
-converges to
. We will show that
converges to
h in
. Let
and
. Since
is finitely equi-Lebesgue and
K is compact, there is a finite family
of
subsets of
K such that
and
for every
and every
. For every
, pick
. There is
such that for every
and every
, we have
Let
and
. There is
such that
. Then, we have
□
Let and be metric spaces. Denote by the set of all functions from such that for every , there is a neighborhood of x with totally bounded in .
Lemma 3. Let be a locally compact metric space and be a metric space. is a closed set in .
Proof. If and , then is a totally bounded set in . Let in . Let and be a compact neighborhood of x. We show that is totally bounded. Let . There is . Then, . Since is totally bounded, there is a finite set such that . We have . Since was arbitrary, is a totally bounded set in . □
Proposition 6. Let be a hemicompact metric space and be a metric space. If is compact, then is finitely equi-Lebesgue family.
Proof. Let
and
. Let
L be an open subset of
X with
and
compact. There are
such that
Since
for every
,
is a totally bounded set in
for every
. Thus,
is totally bounded in
. Let
be a finite set in
Y such that
. For each
and
, let
where
. Since
X is a Baire space, by Corollary 1,
is dense in
X for every
.
For each
, let
be an open neighbourhood of
z such that
and
. Let
The set is a set for every , and . If , then H is a set and, of course, nowhere dense.
We show that . The set is open and dense in . Let U be a nonempty open set in . There is a nonempty open set in X such that . Choose some . Then, for every , for some . Thus, , i.e.,
Let . Then, . Let be such that . Thus, for every , there is such that and then . is proved.
Let be the family that contains all nonempty sets from and . It is easy to see that for every and for every , . □
From the following Theorem, we obtain the main result of our paper for locally bounded Baire 1 functions with values in metric spaces in which every bounded set is totally bounded.
Theorem 3. Let be a hemicompact metric space and be a metric space. is compact in if and only if is finitely equi-Lebesgue family, is closed in , and is compact for every .
Proof. If is compact in , then by Proposition 6, is finitely equi-Lebesgue family. Of course, has to be closed in . Since for every the evaluation map defined by is continuous, is compact for very .
Suppose now that
is finitely equi-Lebesgue family,
is closed in
, and
is compact for every
. We will prove that
is compact in
. Put
Then, the space L is compact with the relative product topology from and . Let be a sequence in . There is , which is a cluster point in L. It is easy to verify that family is finitely equi-Lebesgue family, and by Proposition 5, f is a cluster point of in the topology of uniform convergence on compacta. Without loss of generality, we can suppose that converges to f in the topology of uniform convergence on compacta. By Proposition 2, . By Lemma 3 . Since is a closed set in , . □
Let and be metric spaces. Denote by the family of all locally bounded Baire 1 functions from X to Y. From Theorem 3, we obtain the following main results of our paper.
Corollary 5. Let be a hemicompact metric space and be a metric space in which every bounded set is totally bounded. is compact in if and only if is finitely equi-Lebesgue family, is closed in , and is compact for every .
Corollary 6. Let be a hemicompact metric space and be a boundedly compact metric space. is compact in if and only if is finitely equi-Lebesgue family, is closed in , and is compact for every .
Corollary 7. is compact in if and only if is finitely equi-Lebesgue family, is closed in , and is compact for every .
Example 2. From Corollary 7 and Example 1, we can deduce that the family in Example 1 is not finitely equi-Lebesgue family. In fact, family is not finitely equi-Lebesgue at the point . Suppose that is finitely equi-Lebesgue at . Then for , there exists a finite family of nonempty subsets of X that are either open or nowhere dense such that is a neighborhood of and such that for every , for every , . Without loss of generality, we can suppose that . There must exist such that is infinite. Then, for every , , a contradiction.
Example 3. Let and be equipped with the induced topology from . Y is a metric space in which every bounded set is totally bounded. Let be defined as follows: for and otherwise. Put , and for every , , define as follows: , if , if and otherwise. It is easy to verify that the sequence converges to f in . By Corollary 5, the family is finitely equi-Lebesgue.