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Publicly Available Published by De Gruyter May 19, 2017

A note on properties of the restriction operator on Sobolev spaces

  • David P. Hewett and Andrea Moiola EMAIL logo

Abstract

In our companion paper [3] we studied a number of different Sobolev spaces on a general (non-Lipschitz) open subset Ω of n, defined as closed subspaces of the classical Bessel potential spaces Hs(n) for s. These spaces are mapped by the restriction operator to certain spaces of distributions on Ω. In this note we make some observations about the relation between these spaces of global and local distributions. In particular, we study conditions under which the restriction operator is or is not injective, surjective and isometric between given pairs of spaces. We also provide an explicit formula for minimal norm extension (an inverse of the restriction operator in appropriate spaces) in a special case.

MSC 2010: 46E35

1 Preliminaries

We study properties of Sobolev spaces on a general (non-Lipschitz) open set Ωn. In our companion paper [3] we studied two types of spaces: those consisting of distributions on n (specifically, H~s(Ω), H̊s(Ω), HΩ¯s, defined below), and those consisting of distributions on Ω itself (specifically, Hs(Ω) and H0s(Ω), again defined below). In this note we study properties of the restriction operator as a mapping between the two types of spaces. The results presented here, while elementary, do not seem to be available in the literature, which generally focuses on the more standard Lipschitz case (cf., e.g., [9]). As in [3], our motivation is the study of integral equations on non-Lipschitz sets. (For a concrete example, see [3, §4], where we consider boundary integral equation reformulations of wave scattering problems involving fractal screens.)

We begin by defining the Sobolev spaces involved. Our presentation follows that of [3], which in turn is broadly based on [9]. Given n, let 𝒟(n) denote the space of compactly supported smooth test functions on n, and for any open set Ωn, let 𝒟(Ω):={u𝒟(n):suppuΩ}. For Ωn, let 𝒟*(Ω) denote the space of distributions on Ω (anti-linear continuous functionals on 𝒟(Ω))[1]. Let 𝒮(n) denote the Schwartz space of rapidly decaying smooth test functions on n, and 𝒮*(n) the dual space of tempered distributions (anti-linear continuous functionals on 𝒮(n)). For u𝒮(n), we define the Fourier transform u^(𝝃):=1(2π)n/2ne-i𝝃𝐱u(𝐱)d𝐱, 𝝃n, extending this definition to 𝒮*(n) in the usual way. We define the Sobolev space Hs(n) by

Hs(n):={u𝒮*(n):uHs(n)<},where uHs(n)2=n(1+|𝝃|2)s|u^(𝝃)|2d𝝃,

which is a Hilbert space with the inner product

(u,v)Hs(n)=n(1+|𝝃|2)su^(𝝃)v^(𝝃)¯d𝝃.

For any -<s<t<, Ht(n) is continuously embedded in Hs(n) with dense image, and we have uHs(n)<uHt(n) for all 0uHt(n). Recalling that (𝜶u/𝐱𝜶)(𝝃)=(i𝝃)𝜶u^(𝝃) and |𝜶|:=j=1nαj for a multi-index 𝜶0n, by Plancherel’s theorem it holds that

(1.1)(u,v)Hm(n)=𝜶0n,|𝜶|m(m|𝜶|)(|𝜶|𝜶)n|𝜶|u𝐱𝜶(𝐱)|𝜶|v¯𝐱𝜶(𝐱)d𝐱,m0.

Hence, functions with disjoint support are orthogonal in Hm(n) for m0. But we emphasise that this is not in general true in Hs(n) for s0.

For a closed Fn, we define HFs:={uHs(n):supp(u)F}. The question of whether a given set En can support nontrivial elements of Hs(n) will be important in what follows. This question was investigated in detail in [5], where we introduced the concept of s-nullity. (This concept is referred to by some authors as (2,-s)-polarity, see, e.g., [8, §13.2].)

Definition 1.1.

For s, we say that a set En is s-null if there are no non-zero elements of Hs(n) supported entirely inside E (equivalently, if HFs={0} for every closed set FE).

There are many different ways to define Sobolev spaces on an open subset Ωn. In [3] we studied the following three spaces, all of which are closed subspaces of Hs(n), hence Hilbert spaces with respect to the inner product inherited from Hs(n):

HΩ¯s:={uHs(n):supp(u)Ω¯},s,
H~s(Ω):=𝒟(Ω)¯Hs(n),s,
H̊s(Ω):={uHs(n):u=0 a.e. in Ωc}
={uHs(n):m(suppu(Ωc))=0},s0;

here m() denotes the Lebesgue measure on n. (We note that H̊s(Ω) can also be identified with the set of functions defined on Ω which can be extended by zero to produce functions of the same Sobolev regularity on the whole of n, see Remark 2.4.) These three spaces satisfy the inclusions

H~s(Ω)H̊s(Ω)HΩ¯s

(with H̊s(Ω) present only for s0). If Ω is sufficiently smooth (e.g., C0), then the three sets coincide, but in general all three can be different (this issue is studied in [3, §3.5]).

Another way to define Sobolev spaces on an open set Ω is by restriction from Hs(n). For s, let

Hs(Ω):={u𝒟*(Ω):u=U|Ω for some UHs(n)},uHs(Ω):=minUHs(n)U|Ω=uUHs(n),

where U|Ω denotes the restriction of the distribution U to Ω in the standard sense (cf. [9, p. 66]). The inner product on Hs(Ω) can be written as (u,v)Hs(Ω):=(QsU,QsV)Hs(n) for u,vHs(n), where U,VHs(n) are such that U|Ω=u, V|Ω=v and Qs is the orthogonal projection Qs:Hs(n)(HΩcs), see [3, §3.1.4]. It follows that the restriction operator

(1.2)|Ω:(HΩcs)Hs(Ω) is a unitary isomorphism.

We also introduce the closed subspace of Hs(Ω) defined by

H0s(Ω):=𝒟(Ω)¯|ΩHs(Ω).

The question of when Hs(Ω) and H0s(Ω) are equal is studied in detail in [3, §3.6].

For any open set Ωn, closed set Fn and s, the following dual space realisations hold, in the sense of unitary isomorphism (see [3, §3.2]):

(1.3){(Hs(Ω))*=H~-s(Ω),(H~s(Ω))*=H-s(Ω),(HFs)*=(H~-s(Fc)),(H0s(Ω))*=(H~-s(Ω)HΩ-s),H~-s(Ω).

The duality pairings corresponding to these realisations are defined in terms of the duality pairing

u,vHs(n)×H-s(n)=nu^(𝝃)v^(𝝃)¯d𝝃,

which extends the L2(n) scalar product.

2 Properties of the restriction operator |Ω:Hs(n)Hs(Ω)

In this section we examine the relationship between the spaces H~s(Ω), H̊s(Ω), HΩ¯sHs(n), whose elements are distributions on n, and the spaces Hs(Ω) and H0s(Ω), whose elements are distributions on Ω. The two types of spaces are linked by the restriction operator |Ω:Hs(n)Hs(Ω), and in this section we investigate some of its properties. In particular, we ask: for a given value of s and an appropriate pair of subspaces XHs(n), YHs(Ω), when is |Ω:XY (i) injective? (ii) surjective? (iii) a unitary isomorphism?

We start by recalling that |Ω:XHs(Ω) is continuous with norm at most one for any subspace XHs(n) and that |Ω:(HΩcs)Hs(Ω) is a unitary isomorphism.

For Ω being Lipschitz with bounded Ω, we have the following result, which states that |Ω:H~s(Ω)H0s(Ω) is an isomorphism for certain values of s. (As in [3, 9], we say that Ω is Lipschitz if its boundary can be locally represented as the graph, suitably rotated, of a Lipschitz function from n-1 to , with Ω lying only on one side of Ω.) The result for s0 is classical (see, e.g., [9, Theorem 3.33]); the extension to -1/2<s<0 is proved below (it is an immediate consequence of Lemma 2.7(i) and [3, Corollary 3.29 (ix)]). In interpreting this result one should recall that for Ω being Lipschitz, it holds that H0s(Ω)=Hs(Ω) if and only if s1/2 [3, Corollary 3.29 (ix)] and also that H~s(Ω)=H̊s(Ω)=HΩ¯s for all s (see [3, Lemma 3.15], which follows from [9, Theorems 3.29 and 3.21]), with H̊s(Ω) present only for s0.

Lemma 2.1.

If Ω is Lipschitz, Ω is bounded, and s>-1/2, s{1/2,3/2,}, then |Ω:H~s(Ω)H0s(Ω) is an isomorphism (with norm at most one).

We would like to understand to what extent this result generalises to non-Lipschitz Ω, and also how |Ω acts on the spaces H̊s(Ω) and HΩ¯s in the case where these are not equal to H~s(Ω). Some partial results in this direction are provided by the following lemma.

Lemma 2.2.

Let ΩRn be open and let sR. Then the following hold:

  1. |Ω:HΩ¯sHs(Ω) is injective if and only if Ω is s-null.

  2. For s0, |Ω:H̊s(Ω)Hs(Ω) is injective; if s0, then it is a unitary isomorphism onto its image in Hs(Ω).

  3. For s0, |Ω:H~s(Ω)H0s(Ω) is injective and has dense image; if s0, then it is a unitary isomorphism onto H0s(Ω).

Proof.

Part (i) is obvious from the definition of the restriction operator. For part (ii), the injectivity statement is obvious, since if uH̊s(Ω) and u|Ω=0, then u=0. It follows that |Ω:H̊s(Ω)Hs(Ω) is a unitary isomorphism onto its image in Hs(Ω) when s0, because in this case the Hs(n) inner product (see (1.1)) can be written as a sum of integrals over products of functions/derivatives in the “physical” space (as opposed to the Fourier space), so disjoint support is enough to guarantee orthogonality. Hence, when s0, we have H̊s(Ω)(HΩcs), and we know by (1.2) that |Ω is a unitary isomorphism from (HΩcs) onto Hs(Ω). Part (iii) follows from part (ii) and the density of 𝒟(Ω) in both H~s(Ω) and H0s(Ω) (since the image of a closed set under an isometry is closed). ∎

Remark 2.3.

By combining Lemma 2.2(i) with the results concerning s-nullity in [3, Lemma 3.10] (see also [5]) one can derive a number of corollaries. For example, the following hold:

  1. For every open Ω, there exists -n/2sΩn/2 such that |Ω:HΩ¯sHs(Ω) is always injective for s>sΩ and never injective for s<sΩ. In particular, |Ω:HΩ¯sHs(Ω) is always injective for s>n/2 and never injective for s<-n/2.

  2. If Ω is Lipschitz (even with unbounded boundary), then |Ω:H~s(Ω)=HΩ¯sHs(Ω) is injective if and only if s-1/2.

  3. For every -1/2s*0, there exists a C0 open set Ω for which |Ω:H~s(Ω)=HΩ¯sHs(Ω) is injective for all s>s* and not injective for all s<s*.

Remark 2.4.

To expand on Lemma 2.2(ii), we note that the restriction operator

|Ω:H̊s(Ω){uHs(Ω):uzeHs(n)}Hs(Ω)

is a bijection, where we denote by uze the extension of uHs(Ω) from Ω to n by zero and uuze is the inverse of |Ω, see also [3, Remark 3.1].

Remark 2.5.

Lemma 2.2(iii) and [3, Remark 3.32], which follows from [7, Chapter 1, Theorem 11.7], imply that if Ω is C and bounded, and if s{1/2,3/2,}, then the restriction |Ω:H~s(Ω)H0s(Ω) is not surjective, demonstrating the sharpness of Lemma 2.1.

Remark 2.6.

If Ω is a Lipschitz open set with bounded boundary, Lemma 2.1 and the definition of Hs(Ω) give that |Ω:H~s(Ω)H1(n)H0s(Ω)H1(Ω) is an isomorphism for all 0s1, s1/2. Then [9, Theorem 3.40] gives that:

  1. |Ω:H~s(Ω)H1(n)H1(Ω) is an isomorphism for 0s<1/2,

  2. |Ω:H~s(Ω)H1(n)H01(Ω) is an isomorphism for 1/2<s1.

Characterising (H~1/2(Ω)H1(n))|Ω and deriving similar results for non-Lipschitz sets appear to be open problems.

Lemma 2.2(ii) and (iii) only deal with the case s0. In the next lemma we relate properties of the restriction operator acting on H~s(Ω) for s and -s. In particular, this lemma allows us to infer the statement of Lemma 2.1 for -1/2<s<0 from the classical statement for 0<s<1/2 (recalling that H0s(Ω)=Hs(Ω) for Ω being Lipschitz and s1/2). For clarity, in this lemma and its proof we denote the restriction operator acting on H~s(Ω) as |Ωs:H~s(Ω)Hs(Ω). The proof of the lemma makes use of the fact that we can characterise the Banach space adjoint of |Ωs in terms of |Ω-s, using the dual space realisations (1.3).

Lemma 2.7.

Let ΩRn be non-empty and open, and let sR. Then the following hold:

  1. |Ωs:H~s(Ω)Hs(Ω) is bijective if and only if |Ω-s:H~-s(Ω)H-s(Ω) is bijective.

  2. |Ω-s:H~-s(Ω)H-s(Ω) is injective if and only if |Ωs:H~s(Ω)Hs(Ω) has dense image; i.e., if and only if H0s(Ω)=Hs(Ω).

Proof.

Let s:H-s(Ω)(H~s(Ω))* and s*:H~s(Ω)(H-s(Ω))* be the unitary isomorphisms defined in [3, equation (21)] as follows:

su(v)=U,vsands*v(u)=v,U-sfor uH-s(Ω),vH~s(Ω),

where UH-s(n) denotes any extension of u with U|Ω=u. Let |Ωs*:(Hs(Ω))*(H~s(Ω))* denote the Banach space adjoint (i.e., the transpose) of |Ωs, defined by (|Ωs*l)(ϕ)=l(ϕ|Ωs) for l(Hs(Ω))* and ϕH~s(Ω). We can characterise |Ωs* in terms of |Ω-s, using s and -s*. Precisely, it holds that |Ωs*-s*=s|Ω-s. To see this, simply note that, by the definition of s and -s*,

(|Ωs*-s*u)(v)=(-s*u)(v|Ωs)=u,vs=(s(u|Ω-s))(v),uH~-s(Ω),vH~s(Ω).

From this characterisation, the statements of the lemma follow immediately using classical functional-analytic results, e.g., [1, Corollary 2.18 and Theorem 2.20]. ∎

We have seen that the restriction operator |Ω:H~s(Ω)H0s(Ω) is an isomorphism for Ω being Lipschitz and for s>-1/2, s{1/2,3/2,}. The next proposition shows that this result also extends to the case where Ω is a finite union of disjoint Lipschitz open sets, even when the union is not itself Lipschitz. Note that we do not require the closures of the constituent open sets to be mutually disjoint. The result therefore applies, for example, to the prefractal sets generating the Sierpinski triangle [3, Figure 4 (a)], which are finite unions of equilateral triangles touching at vertices.

Proposition 2.8.

The statements of Lemma 2.1 extend to finite disjoint unions of Lipschitz open sets with bounded boundaries.

Proof.

The injectivity statement follows from the s-nullity of finite unions of Lipschitz boundaries for s-1/2 (cf. [3, Lemma 3.10 (v) and (xix)]). The surjectivity follows from Lemma 2.9 below. ∎

Lemma 2.9.

Let the open set ΩRn be the union of the disjoint open sets {Aj}j=1N, NN, and suppose that the restrictions |Aj:H~s(Aj)H0s(Aj) are surjective for all 1jN. Then also |Ω:H~s(Ω)H0s(Ω) is surjective.

Proof.

In this proof we denote by |Ω1,Ω2 the restriction operator from 𝒟*(Ω1) to 𝒟*(Ω2), when Ω2Ω1n are open sets. Fix uH0s(Ω). Then, for all 1jN, u|Ω,AjHs(Aj) belongs to H0s(Aj), since Ω is a disjoint union and so (𝒟(Ω)|n,Ω)|Ω,Aj=𝒟(Aj)|n,Aj. By assumption, u|Ω,Aj=wj|n,Aj for some wjH~s(Aj)H~s(Ω). Finally, w:=j=1NwjH~s(Ω) satisfies w|n,Ω=u (using the fact that any test function ϕ𝒟(Ω) can be uniquely decomposed as a sum ϕ=j=1Nϕj, where ϕj𝒟(Aj)), and this shows that u is in the range of |n,Ω, as required. ∎

For s0, we can rephrase the results of this section as follows. For any open set Ω, the restriction operator |Ω:H~s(Ω)H0s(Ω) is continuous with norm one, is injective, has dense image, and the zero extension uuze is its right inverse on its image, i.e., uze|Ω=u for all uH~s(Ω)|Ω. Furthermore, for s0, the following conditions are equivalent:

  1. |Ω:H~s(Ω)H0s(Ω) is an isomorphism,

  2. |Ω:H~s(Ω)H0s(Ω) is surjective,

  3. the zero extension uuze is continuous H0s(Ω)H~s(Ω),

  4. there exists c>0 such that ΦHs(n)cϕHs(n) for all ϕ𝒟(Ω) and ΦHs(n) such that Φ|Ω=ϕ.

By Proposition 2.8, we know all these conditions hold for disjoint unions of Lipschitz open sets with bounded boundary and s{1/2,3/2,}. But results about the surjectivity (or otherwise) of |Ω:H~s(Ω)H0s(Ω) on more general Ω do not seem to be available in the literature and in this case we only know (by Lemma 2.2iii) that the conditions above are true for s0. The following therefore appear to be open questions: For which Ω are (i)–(iv) true for all s>-1/2, s{1/2,3/2,}? For which values of s are they satisfied for a given Ω?

2.1 When is |Ω:H~s(Ω)H0s(Ω) a unitary isomorphism?

To study when |Ω:H~s(Ω)H0s(Ω) is a unitary isomorphism, we first note the equivalences in the following lemma. We emphasise that the norm on the left-hand side of the equality in part (ii) in the lemma is the minimal one among the Hs(n)-norms of all the extensions of ϕ|Ω, while that on the right-hand side uses ϕ=0 in Ωc.

Lemma 2.10.

Let Ω be a non-empty open subset of Rn and let sR. The following are equivalent:

  1. |Ω:H~s(Ω)H0s(Ω) is a unitary isomorphism,

  2. ϕ|ΩHs(Ω)=ϕHs(d) for all ϕ𝒟(Ω),

  3. 𝒟(Ω)(HΩcs).

Proof.

The implications (i)(ii) and (iii)(i) are trivial (the latter holding by the density of 𝒟(Ω) in H~s(Ω) and (1.2)). (ii)(iii) follows because |Ω:(HΩcs)Hs(Ω) is an isometry (cf. (1.2)). Explicitly, if ϕ𝒟(Ω), then ϕ=ϕ1+ϕ2 for a unique pair ϕ1(HΩcs) and ϕ2HΩcs. It follows that ϕHs(d)=ϕ1Hs(d)+ϕ2Hs(d), and that ϕ|ΩHs(Ω)=ϕ1|ΩHs(Ω)=ϕ1Hs(d). So, if the equality in (ii) holds, we must have that ϕ2=0, i.e., ϕ(HΩcs). ∎

Lemma 2.10 allows us to prove the following proposition, which shows that the unitarity property holds whenever the complement of Ω is negligible (in the sense of s-nullity). An extreme example is the punctured space Ω=n{𝟎}, for which the proposition holds for any s-n/2.

Proposition 2.11.

Let sR, and let Ω be an open subset of Rn such that Ωc is s-null. Then |Ω:H~s(Ω)H0s(Ω) is a unitary isomorphism.

Proof.

The assumption that Ωc is s-null means that (HΩcs)=({0})=Hs(n)𝒟(Ω). Therefore, part (iii) of Lemma 2.10 holds and hence the result follows. ∎

Conversely, we can demonstrate that when the complement of Ω is not negligible, |Ω:H~s(Ω)H0s(Ω) is not in general a unitary isomorphism except when s0.

Proposition 2.12.

Assume that Ω is non-empty, open and bounded. Then the three equivalent statements in Lemma 2.10 hold if and only if s is a non-negative integer.

Proof.

We have seen in Lemma 2.2(iii) that |Ω:H~s(Ω)H0s(Ω) is a unitary isomorphism when s0, for any Ω. When s0 and Ω is bounded, we shall prove that this does not hold by showing that statement (iii) of Lemma 2.10 fails. Take any ϕ𝒟(Ω) and define the translate ϕ𝐝(𝐱):=ϕ(𝐱-𝐝) for 𝐝n. Then ϕ𝐝𝒟(n). In fact, since Ω is assumed bounded, for large enough |𝐝|, we have that ϕ𝐝𝒟(Ω¯c)HΩcs, so that in particular suppϕsuppϕ𝐝 is empty. Define χ(𝐝):=(ϕ,ϕ𝐝)Hs(n)=(ϕ(),ϕ(-𝐝))Hs(n). Then the formula for the Fourier transform of a translate gives

χ(𝐝)=(ϕ,ϕ𝐝)Hs(n)=nei𝐝𝝃μ(𝝃)d𝝃,

where

μ(𝝃):=(1+|𝝃|2)s|ϕ^(𝝃)|2=(1+ξ12++ξn2)s|ϕ^(𝝃)|2,with 𝝃=(ξ1,,ξn).

Since μ(𝝃) is an element of 𝒮(n), χ(𝐝) is also an element of 𝒮(n), with Fourier transform χ^(𝝃)=(2π)n/2μ(𝝃). But for s0,1,2,, the function μ(𝝃) does not extend to an entire function on n because the factor (1+ξ12++ξn2)s has singularities in n. (For example, for n=1, these singularities occur at the points 𝝃=±i.) Hence, by the Paley–Wiener theorem (see, e.g., [4, Theorem 2.3.21]) χ(𝐝) cannot have compact support in n. As a result, we can always find 𝐝, with |𝐝| large enough, that ϕ𝐝𝒟(Ω¯c)HΩcs and χ(𝐝)=(ϕ,ϕ𝐝)Hs(n)0. ∎

Remark 2.13.

In proving the “only if” statement in Proposition 2.12, we required Ω to be bounded. With minor modifications, the same proof works for some unbounded Ω. A first example is when Ωc is bounded with non-empty interior. A second example is when either Ω itself or Ω¯c, the interior of the complement of Ω, assumed to be non-empty, is contained in the hypograph {𝐱n,xn>g(x1,,xn-1)}, where g:n-1 satisfies lim|𝐱~|g(𝐱~)=; the proof of Proposition 2.12 works in this case because χ(-𝐝)=χ(𝐝)¯. The result does not hold for every open set Ω, as Proposition 2.11 demonstrates. However, we conjecture that the statement of Proposition 2.12 holds for any Ω for which Ωc has non-empty interior. But proving this conjecture appears to be an open problem.

Remark 2.14.

Proposition 2.12 illustrates the fact that Sobolev norms with non-natural-number indices are non-local. In particular, it implies that given any s0, any ϕ𝒟(n) and any (arbitrarily large) bounded set Ω containing the support of ϕ, there exists ψ𝒟(n) with support in Ωc such that

ϕ+ψHs(n)<ϕHs(n).

As an illustrative example, we exhibit a sequence {ΦN}N0H-1() of distributions with compact support suppΦN[0,2N] such that each one of them is an extension of the preceding one (that is to say ΦN+1|(-,2N+1/2)=ΦN|(-,2N+1/2) for all N0) and their norms are strictly decreasing in N, in other words ΦN+1H-1()<ΦNH-1(). Such a sequence can be defined as follows: choose any 0<α<1/e and set (where δx denotes the Dirac delta[2] centred at x)

Φ0:=δ0,ΦN:=k=02N(-α)kδk=ΦN-1-α2N-1δ2N-1+α2Nδ2N,N.

The Fourier transform formula δ^x=12πeixξ and the identity (1+ξ2)-1eiaξdξ=πe-|a| imply that the H-1()-scalar product of two delta functions is

(2.1)(δx,δy)H-1()=12e-|x-y|,

giving

ΦNH-1()2=12k=02Nα2k+0j<k2N(-α)j+ke-(k-j).

With some manipulations, it is not difficult to prove that every extension strictly reduces the norm:

ΦNH-1()2-ΦN-1H-1()2=-α4N-22(1+αe)((1+α2)(1-αe)+2(1-αe)(αe)1-2N)<0.

We point out that while the sequence {ΦNH-1()}N=1 is decreasing, our results in §3 (equation (3.1) in particular) imply that for every N0, the extension of ΦN|(-,2N+1/2) with minimal H-1(n) norm is supported in (-,2N+1/2] and has the expression ΦN+cδ2N+1/2 for some c.

3 The space (HΩcs) and minimal norm extensions

From (1.2), the elements of (HΩcs) are the extensions of the elements of Hs(Ω) with minimal Hs(n) norm. In this short section we make some remarks on the nature of the elements of (HΩcs), and on minimal norm extensions. We also refer the reader to the related discussion in Remark 2.14 above.

For m0, the fact that functions with disjoint support are orthogonal in Hm(n) (cf. (1.1) and the sentence following it) implies that H̊m(Ω)(HΩcm). Thus, we have

H~m(Ω)H̊m(Ω)(HΩcm)(H~m(Ω¯c)),m0,

which, by duality (1.3), implies that

(HΩc-m)H~-m(Ω)HΩ¯-m,m0.

In particular, minimal extensions from H-m(Ω) to H-m(n) are supported in Ω¯. Hence, if uH-m(Ω), then there exists UHΩ¯-m with U|Ω=u. Furthermore, given any such U, the minimal extension of u is given by Q-mU=U+w, where wHΩ-m.

For example, if Ω=(a,b), then the action of Q-m on UHΩ¯-m can be written explicitly, since HΩ-m is finite-dimensional and its elements are (derivatives of) delta functions supported in Ω={a,b}. In particular, for UHΩ¯-1,

(3.1)Q-1U=U+caδa+cbδbfor some ca,cb.

Using (2.1), the minimisation of U+caδa+cbδbH-1()2 shows that

ca=(U,δb)H-1()-eb-a(U,δa)H-1()sinh(b-a),cb=(U,δa)H-1()-eb-a(U,δb)H-1()sinh(b-a).

For instance, if uH-1(Ω) is given by u=δx for some a<x<b (viewed as a distribution on Ω=(a,b)), then clearly U:=δx (viewed as a distribution on ) is an extension of u, whose projection onto (HΩc-1) is given by (3.1). In this case, the choice of ca,cb that minimises the H-1(n) norm of (3.1) is

ca=-sinh(b-x)sinh(b-a),cb=-sinh(x-a)sinh(b-a),

which give

δxH-1(Ω)2=δx+caδa+cbδbH-1()2=sinh(b-x)sinh(x-a)sinh(b-a)<12=δxH-1()2.

However, in general, (HΩcs)HΩ¯s when -s0, i.e., the elements of (HΩcs) do not generally have their support in Ω¯. Explicit expressions for the minimal-norm extensions of the elements of H1(Ω) and H2(Ω) for the special case Ω=(a,b) have been presented in [2, Lemma 4.12] and lead to the following formulae for the norms:

ϕH1(Ω)2=|ϕ(a)|2+|ϕ(b)|2+ab(|ϕ|2+|ϕ|2)dx,
ϕH2(Ω)2=|ϕ(a)|2+|ϕ(a)|2+|ϕ(a)-ϕ(a)|2+|ϕ(b)|2+|ϕ(b)|2
+|ϕ(b)+ϕ(b)|2+ab(|ϕ|2+2|ϕ|2+|ϕ′′|2)dx.

(Note that we have corrected a sign typo present in [2, equation (26)].)

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Received: 2016-7-11
Accepted: 2017-4-7
Published Online: 2017-5-19
Published in Print: 2017-6-1

© 2017 Walter de Gruyter GmbH, Berlin/Boston

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