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BY 4.0 license Open Access Published by De Gruyter April 14, 2021

Half-space Gaussian symmetrization: applications to semilinear elliptic problems

  • J. I. Díaz , F. Feo and M. R. Posteraro EMAIL logo

Abstract

We consider a class of semilinear equations with an absorption nonlinear zero order term of power type, where elliptic condition is given in terms of Gauss measure. In the case of the superlinear equation we introduce a suitable definition of solutions in order to prove the existence and uniqueness of a solution in ℝN without growth restrictions at infinity. A comparison result in terms of the half-space Gaussian symmetrized problem is also proved. As an application, we give some estimates in measure of the growth of the solution near the boundary of its support for sublinear equations. Finally we generalize our results to problems with a nonlinear zero order term not necessary of power type.

MSC 2010: 35J61; 35J70; 35B45

1 Introduction

In this paper we focus our attention on a class of semilinear elliptic Dirichlet problems, whose prototype is

(1.1) div(u(x)φ(x))+c0u(x)p1u(x)φ(x)=f(x)φ(x)inΩu=0onΩ,

where c0 > 0, p > 0, Ω is an open subset of ℝN not necessary bounded, φ(x)=φN(x):=(2π)N2exp|x|22 is the density of standard N−dimensional Gauss measure γ and the datum f belongs to a suitable Zygmund space. A more general diffusion operator is in fact considered in all this paper.

Problem (1.1) is related to Ornstein-Uhlenbeck operator Lu≔ Δ u − x·∇ u and our approach allows us to consider an extra semilinear zero order term c0up−1u, Ω=ℝN and a weak assumption on the summability of datum. Notice that we can formally write div(∇ uφ(x))=Δ uφ(x)+∇φ(x)·∇ u which justifies the multiplicative role of φ(x) in the equation of (1.1). The idea of “ symmetrizing the operator” −Δu(x)+x·∇ u in order to solve the drift equation

(1.2) Δu(x)+xu+c0u(x)p1u(x)=f(x)inΩu=0onΩ,

comes back from a pioneering paper [27] by Kolmogorov in 1937 for c0=0. For some recent survey in this direction see [32]. It is well-known the above diffusion operator with a drift is related to the stochastic Ornstein–Uhlenbeck process with applications in financial mathematics and in physical sciences (a model for the velocity of a massive Brownian particle under the influence of friction). This is sometimes also written in terms of a Langevin ordinary differential equation with noise (see, e.g. [31]).

We remark that if φ ≡ 1 problem (1.1) was largely considered in the literature (see, e.g. [9] when Ω is bounded and [37] and [19] when Ω is unbounded and p > 1).

In the weighted case, when p ⩽ 1 and γ (Ω)<1, Lax-Milgram Theorem guarantees the existence of a solution for problem (1.1) uH01(Ω,γ) (the weighted Sobolev space) once we assume f belongs to its dual. For example we can require fL2logL12(Ω,γ) , a functional space which we recalled in Section 2, where other preliminary notions will also be collected.

If we consider Ω=ℝN one of the difficulties that arises when solving (1.1) is due to lack of a Poincaré inequality. As a consequence we have to consider the Banach space H1(ℝ N, γ) equipped with the norm ∣∣ u∣∣L2(ℝN,γ)+∣∣∇ u∣∣L2(ℝN,γ). In the linear case, p=1, the existence and uniqueness of a weak solution u ∈ H1(ℝN, γ) to (1.1) follows again from Lax-Milgram Theorem and we also get the correct growth condition on f(x) as ∣ x∣ → +∞ (see, e.g. the exposition made in [30]).

The superlinear case p > 1 is different. In Section 3 we shall prove the existence and uniqueness giving a suitable notion of weak solution for the case of Ω=ℝN and p > 1. We point out that in the superlinear case when γ (Ω)<1 the existence and uniqueness of a weak solution can be obtained through an easy adaptation of the results of Brezis and Browder [9]. In order to consider Ω=ℝN we follow an idea of [19], giving an alternative proof and enlarging the applications of the pioneering result on superlinear problems by Brezis [8]. Thanks to the assumption p > 1 we get some a priori estimates on any given half-space allowing us to obtain a general existence and uniqueness result without any growth condition at infinity on the datum f (and so with less summability than f in L2logL12(RN,γ)).

In a second part of the paper (Sections 4 and 5) we deal with comparison results in terms of the half-space Gaussian symmetrization of solutions of (1.1) and its generalizations. We point out that when Ω is bounded the usual radially symmetrization method, when applied to an elliptic operator with a drift term as (1.2) modifies drastically the drift term in the symmetrized equation (see, e.g., [34]). In contrast to that, the half-space Gaussian symmetrization method allows to preserve the more important facts of the drift term (see Remark 11) as well as to deal with an unbounded domain. We recall that in [3] the authors compare the solution u to problem (1.1), when γ (Ω)<1, with the solution v to a simpler problem, called the half-space Gaussian symmetrized problem, without zero order term defined in the half-space Ω ={(x1, ..., xN) ∈ ℝN:x1>ω } with ω such that γ (Ω )=γ (Ω) and with a datum depending only on the first variable. Here we are interested to prove some comparisons in term of the solution to symmetrized problem keeping also a nonlinear zero order term. As in the unweighted case (see e.g. [16], [18]) we are able to obtain some integral estimates, that imply a comparison between Lebesgue norms. Other comparison results related to Gauss measure are contained in [20,21], [12] for the parabolic case and [25] in the non-local case. As an application, we give some estimates in measure of the growth of the solution near the boundary of its support for sublinear equations p ∈ (0, 1) when the datum f possibly vanishes on a positively measured subset of Ω.

Finally in Section 5 we generalize our results to problems with more general zero order terms b(u), not necessary of power type as in previous Sections.

2 Preliminaries

Let γ be the N-dimensional Gauss measure on ℝN defined by

dγ:=φN(x)dx:=(2π)N2exp|x|22dx,xRN

normalized by γ(ℝN)=1. In what follows we will set φN(x)=φ(x) for simplicity.

It is well-known that an isoperimetric inequality for Gauss measure holds (see e.g. [11]): among all measurable sets of ℝN with prescribed Gauss measure, the half-spaces take the smallest perimeter (in the sense of this measure). In particular, the perimeter of a (N − 1)−rectifiable setEofRN with respect to the Gauss measureis defined as

PE=2πN2Eexpx22HN1dx,

where HN1 denotes the (N − 1)−dimensional Hausdorff measure. The following isoperimetric estimate (see e.g. [11])

(2.1) PEφ1(Φ1(γE))

holds for all subsets E⊂ℝn, where φ1(s)=2π12exps22 for sR and

(2.2) Φλ=λ+φ1(s)dsforλR,+,

the 1− dimensional Gauss measure of line (λ, ∞).

Now we introduce the notion of rearrangement with respect to Gauss measure (see e.g. [22]). Here the balls of Schwartz symmetrization is replaced by half-spaces

(2.3) Hω:=x=x1,,xNRN:x1>ω for some ωR{,+}.

If u is a measurable function in Ω, we denote by u the decreasing rearrangement of u with respect to Gauss measure, i.e.

(2.4) u(s)=inft0:γu(t)ss0,1,

where γu(t)=γ({x ∈ Ω:∣ u∣>t}) is the distribution function of u with respect to the Gauss measure. Moreover the rearrangement with respect to Gauss measure of u is defined as

(2.5) u(x)=uΦx1xΩ,

where

(2.6) Ω:=Hω with ω such that γΩ=γ(Ω)

and Φ is defined in (2.2).

By definition u is a function which depend only on the first variable and its level sets are half-spaces. Moreover u, u and u have the same distribution function.

If u(x), v(x) are measurable functions an Hardy-Littlewood inequality hods:

(2.7) ΩuxvxdγΩuxvxdγ=0γΩusvsds.

For general results about the properties of rearrangement with respect to a positive measure see, for example, [13].

We recall that for every open set ΩRN the weighted Lebesgue space Lp (𝛺, 𝛾) with p ≥ 1 is the space of measurable functions u such that

u L p ( Ω , γ ) := Ω | u | p d γ 1 p .

Moreover, as usual, H1(Ω, γ) states for the weighted Sobolev space of functions u such that u, ∣∇ u∣ ∈ L2(Ω, γ) equipped with the norm ∣∣ u∣∣L2(Ω,γ)+∣∣∇ u∣∣L2(Ω,γ). Finally we denote by H01(Ω,γ) the closure of C0(Ω) under the norm ∣∣∇ u∣∣L2(Ω,γ). We remark that a Poincaré inequality holds only when γ (Ω)<1:

(2.8) Ω|u|2dγCPΩu2dγ

for every uH01(Ω,γ) , where CP is a positive constant depending on Ω.

The Sobolev space H01(Ω,γ) is continuously embedded in the Zygmund space L2(logL)12(Ω,γ) (see [26], [24], [23] and references therein). We recall that given 1 ⩽ p<∞ and −∞<α<+∞, a measurable function u belongs to the Zygmund space Lp(logL)α(Ω, γ) if

(2.9) ||u||Lp(logL)α(Ω,γ):=0γΩ(1logt)αu(t)qdt1q<.

Then, it is well-known that there exists a constant CS depending on Ω such that

(2.10) uL2(logL)12(Ω,γ)CSuL2(Ω,γ)

for all uH01(Ω,γ) . This explain why Zygmund spaces are the natural spaces for the data of problems as (1.1). We observe that these spaces give a refinement of the usual Lebesgue spaces. Indeed by definition (2.9) the space Lp(logL)0(Ω, γ)=Lp(Ω, γ). For the definition and properties of the classical Zygmund space we refer to [5].

When Ω=ℝN we explicitly underline that inequality (2.10) holds by replacing the norm of the gradient by the norm of H1(ℝN, γ).

3 Existence and uniqueness of solutions for the superlinear problem in ℝN without growing conditions

In the present section we focus our attention to existence and uniqueness of solutions to problem (1.1) when Ω=ℝN. Precisely we consider the more general second order elliptic problem

(3.1) i,j=1Nxjaij(x)uxi(x)+cxu(x)p1u(x)φ(x)=f(x)φ(x)inRN.

As recalled in the introduction, to deal with Ω=ℝN we will need a suitable definition of weak solution. We refer to [8,19] for unweighted case φ(x) ≡ 1.

We introduce the natural energy space for the linear problem (for the case p=1)

V(RN)={w:wH1(Hω,γ)for anyωR},

where Hω is defined in (2.3). We stress that for a given function f such that fL2(logL)12Hω,γ for any Hω the integrals

Hωfψdγ

are well-defined for any ψ ∈ V (ℝN) (even if f is not necessarily in the dual space of H1(ℝN, γ)).

In this section we will assume the following structural conditions:

  1. p > 1

  2. aijφL(Hω)ωR and i,j=1Naij(x)ξiξjαφ(x)|ξ|2 for a.e. xRN , ∀ ξ ∈ ℝNwith α>0

  3. c ∈ L1(Hω, γ) and c(x) ⩾ c0 > 0 for x ∈ Hω for any ωR

  4. fL2(logL)12(Hω,γ) for any ωR .

Definition 1

A function u ∈ V (ℝN) is a weak solution to problem (3.1) if cup−1u ∈ L1(Hω, γ) for any ωR and

(3.2) i,j=1NRNaijuxiψxjdx+RNcup1uψdγ=RNfψdγ

for every ψ ∈ H1(Hω, γ)∩ L(Hω) with support contained in Hω for any ωR .

We stress that under our assumptions all terms in (3.2) are well-defined. Obviously in Definition (1) we can consider any half-space

{xRN:xξ>ω}ξRNwithξ=1andωR,

not only the ones with boundary perpendicular to e1.

Let us fix ω0 > 0 and let us introduce for any ωR the auxiliary function

Θω(x)=θω2(x1)for anyx1R,

where θω ∈ C(ℝ) is such that θω(x1)=1 for x1ω +ω0 and θω(x1)=0 for x1ω.

Theorem 2

Let us suppose that (A1)-(A4) hold. Then, there exists a unique weak solution in the sense of Definition 1 to problem (3.1) such that cup+1 ∈ L1(Hω, γ) for any ωR and (3.2) holds for ψ=uΘω for any ωR .

Proof

Step 1. Existence. For a given MN let us consider the following localized problem

(P_M)i,j=1Nxjaij(x)uxi(x)+cxu(x)p1u(x)φ(x)=f(x)φ(x)inHMu=0,onHM.

We will adapt Brezis-Browder’s proof (see [9]) to prove the existence and uniqueness of a weak solution uMH01(HM,γ) , i.e. cuMp ∈ L1(HM, γ) and

(3.3) i,j=1NHMaijuMxiψxjdx+HMcuMp1uMψdγ=HMfψdγ

for ψH01(HM)LHM . Moreover we get cuMp+1 ∈ L1(HM, γ) and for ω >−M

(3.4) i,j=1NHωaijuMxixj(uMΘω)dx+HωcuMp+1Θωdγ=HωfuMΘωdγ.

Indeed take ψ=Tm(uM)Θω in (3.3), where

(3.5) Tm(r):=min{m,|r|}sign(r)rRandmN.

When m goes to ∞ we get (3.4).

Finally we extend uM by zero over ℝNHM and we denote again this extension by uM.

Now we prove an estimate of uM, which is independent of M thanks to the crucial assumption p > 1.

Lemma 3

Let us assume that u ∈ H1(HM, γ), cup+1 ∈ L1(HM, γ), ω0 > 0 and for any ω>−M

(3.6) i,j=1NHωaijuxixj(uΘω)dx+Hωcup+1ΘωdγHωfuΘωdγ

holds when fL2logL12(Hω,γ) for any ω >−M. Then

(3.7) Hω+ω0|u|2dγK10+s2(m1)(p+1)p14mp1φ(ω+s)ds+0+s2(m1)(p+1)p1φ(ω+s)ds+K2fL2logL12Hω,γ2

and

(3.8) Hω+ω0|u|p+1dγK10+s2(m1)(p+1)p14mp1φ(ω+s)ds+0+s2(m1)(p+1)p1φ(ω+s)ds+K2fL22logL12Hω,γ

for some positive constant K1 and K2 independent of u, ω, p and f.

proof. Indeed by (A2) and (A3) we get

(3.9) α H ω + ω 0 | u | 2 d γ = α H ω + ω 0 | u | 2 Θ ω d γ α H ω | u | 2 Θ ω d γ i , j = 1 N H ω a i j u x i u x j Θ ω d x = i , j = 1 N H ω a i j u x i x j u Θ ω d x i , j = 1 N H ω a i j u x i Θ ω x j u d x

and

(3.10) c0Hω+ω0|u|p+1dγ=c0Hω+ω0|u|p+1Θωdγc0Hω|u|p+1ΘωdγHωc|u|p+1Θωdγ.

Using (3.6), (3.9) and (3.10) we get

(3.11) αHω|u|2Θωdγ+Hωc0|u|p+1ΘωdγHωfuΘωdγi,j=1NHωaijuxiΘωxjudx.

Since p > 1, by Young inequality we get that

(3.12) i,j=1NHωaijuxiΘωxjudx=i,j=1NHωaijuxixjθω2x1udx2i,j=1NHωaijuxiθωx1θωx1udx2maxi,jaijφHω|u|θωx1θωx1|u|dγ2εmaxi,jaijφHω|u|2Θωdγ+2C(ε)maxi,jaijφωωθωx12|u|2dγ2εmaxi,jaijφHω|u|2Θωdγ+2δC(ε)maxi,jaijφHω|u|p+1Θωdγ+2C(δ,ε)maxi,jaijφωωθωx12(p+1)p1Θω2p1dγ

for some positive constants ε and δ that can be chosen later. Moreover we have

(3.13) HωfuΘωdγCεfL2logL12Hω,γ2+εuΘωL2logL12Hω,γ2

for some positive constant ε′ that can be chosen later. Sobolev inequality (2.10) and Young inequality allow us to obtain

(3.14) uMΘωL2logL12Hω2k0HωuMΘω2dγ+HωuΘω2dγk1γHω+k2Hωu|p+1Θω+k3Hωu2Θωdγ+k4Hωθωx12u2Θωdγ

for some positive constants k0, k1, k2, k3, k4. As before we get

(3.15) Hωθωx12|u|2ΘωdγδHω|u|p+1Θωdγ+CδHωθx12(p+1)p1Θωdγ.

for some positive constant δ′ that can be chosen later. Taking θω(x1)=O|ωx1|m1 with m > 0, then

(3.16) Hωθωx12(p+1)p1Θω2p1x1dγk5Hωωx12(m1)(p+1)p14mp1dγ=k50+S2(m1)(p+1)p14mp1φ(ω+s)ds

for some positive constant k5 and the last integral is finite if m>p+1p1 . Moreover

(3.17) Hωθωx12(p+1)p1Θωx1dγk60+s2(m1)(p+1)p1φ(ω+s)ds

for some positive constant k6 and the last integral is finite if m > 1. Choosing ε, ε′, δ and δ′ small enough and using (3.16), (3.17), (3.15), (3.14), (3.13), (3.12) in (3.11) we get

(3.18) Hω|u|2Θωdγ+Hω|u|p+1Θωdγk70+S2(m1)(p+1)p14mp1φ(ω+s)ds+0+s2(m1)(p+1)p1φ(ω+s)ds+k8fL22logL12Hω,γ

for some positive constant k7, k8. Using (3.9), (3.10) and (3.18) we obtain (3.7) and (3.8). □

Using (3.7) and (3.8) we can conclude that uM is bounded in H1(Hω+ω0,γ) and it follows that there exists u such that (up a subsequence) uM → u weakly in H1(Hω, γ) for any ωR , weakly in Lp+1(Hω, γ) for any ωR , strongly in Lq(Hω, γ) for any ωR with q < p+1 and a.e. in Hω for any ωR . Using these convergences and the monotonicity of function G(s)=∣sp−1s we can pass to the limit in (3.3) and we conclude.

Step 2. Uniqueness. Let u1 and u2 be two different weak solutions to Problem (3.1) such that cu1p+1, cu2p+1 ∈ L1(Hω, γ) for any ωR . We stress that they satisfy (3.2) with ψ=u1Θω and ψ=u2Θω for any ωR . Let v=u1u2. Since v ∈ H1(Hω, γ)\normalcolor∩ Lp+1(Hω, γ) for any ωR we get

i,j=1NRNaijvxi(vΘω)xjdx+RNΓ(x)vp+1Θωdγ=0,

where

Γ ( x ) = c ( x ) u 1 ( x ) p 1 u 1 ( x ) u 2 ( x ) p 1 u 2 ( x ) u 1 ( x ) u 2 ( x ) 1 u 1 ( x ) u 2 ( x )  if  u 1 ( x ) u 2 ( x ) c 0  if  u 1 ( x ) = u 2 ( x ) .

For p > 1 we have Γ(x)=c0 a.e. in ℝN. Then Lemma 3 can be applied obtaining

(3.19) Hω+ω0|uM|2dγK10+s2(m1)(p+1)p14mp1φ(ω+s)ds

and

(3.20) Hω+ω0|uM|p+1dγK10+s2(m1)(p+1)p14mp1φ(ω+s)ds

for some positive constant K1 . Lebesgue’s dominated convergence theorem allows

limω0+s2(m1)(p+1)p14mp1φ(ω+s)ds=0.

Putting ω goes to −∞ we get ∇ v=0 a.e. on ℝN by (3.19) grad v and then v=0 a.e. on ℝN using (3.20). This is a contradiction and the uniqueness result follows.

Remark. 4

Arguing as in the proof of the uniqueness result it is possible to prove that if u1 is a weak supersolution and u2 is a weak solution to problem (3.1), then u1u2 a.e. onN.

Remark. 5

We stress that Definition 1 and Theorem 2 can be easily adapted to problems defined in open subsets of ℝN with γ (Ω)=1.

Remark 6

The hypothesis p > 1 is crucial to prove existence of a weak solution in the sense of Definition 1 relaxing the standard assumption on the datum, namely f belongs to the dual space of H1RN,γ . Otherwise in the case p ⩽ 1 if the datum belongs to the dual space of the energy space, the existence of a solution in H1RN,γ follows arguing as in Theorem 4.2 of [15], because the space H1(ℝN, γ) coincides with H1(ℝN, γ)∩ Lp+1(ℝN, γ) and both topologies are equivalent.

Remark. 7

Since in Theorem 2 the existence (and uniqueness) of solutions is obtained without any decay condition on f it is natural to search about possible decay estimates of the solutions when ∣ x∣ → +∞. The estimates obtained in [19] was extended to other different settings by several authors (see, e.g. [29] and its references).

4 Comparison results in terms of the half-space Gaussian symmetrization

In this section we will give results comparing a solution of problem of type (1.1) with the solution to a simpler problem defined in an half-space having data depending only on one variable.

We need starting with the case γ (Ω)<1 and we consider the following class of Dirichlet problems

(4.1) i,j=1Nxjaij(x)uxi(x)+c(x)|u(x)|p1u(x)φ(x)=f(x)φ(x) in Ωu=0 on Ω.

The structural assumptions (instead of (A1)−(A4)) are now the following:

(A0) Ω is an open subset of ℝN (N=2) such that γ (Ω)<1,

(A1′) p > 0,

(A2′) aijφL(Ω) and i,j=1N aij(x)ξiξjαφ(x)∣ξ2 for a.e. x ∈ Ω, ∀ξ ∈ ℝN with α>0,

(A3′) c ∈ L1(Ω, γ), c(x) ⩾ c0 > 0,

(A4′)f ∈ L2logL−1/2(Ω, γ).

We recall that under assumption (A2′) a Poincaré inequality holds and that f ∈ L2logL−1/2(Ω, γ) can be identified with an element in the dual space of H01(Ω,γ) (Ω, γ) (see [4]). Then, under our assumptions, all terms in the corresponding notion of weak formulation are well-defined using (2.10) and (2.8). Sinceγ (Ω)<1, the existence of a weak solution to (4.1) comes easily by adapting the Brezis-Browder’s proof ([9]). Moreover, the uniqueness of solutions is standard.

The first result of this section shows a suitable integral comparison between the solution u to problem (3.1) and the solution v to the following symmetrized problem

(4.2) div(αv(x)φ(x))+c0|v(x)|p1v(x)φ(x)=f˜(x)φ(x) in Ωv=0 on Ω,

where Ω is the half-space defined in (2.6) and f˜ is such that f˜=f˜ , the rearrangement with respect to Gauss measure of f˜ defined in (2.5).

First of all, we prove that the solution to (4.2) coincides with its half-space Gaussian rearrangement.

Proposition 8

Let assume that f˜L2logL12Ω,γ . Then problem (4.2) has a unique nonnegative weak solution such that v(x)=v(x) in Ω.

Proof.Since f˜=f˜ , then f˜0 . As a consequence the existence of a unique nonnegative weak solution is standard. We only detail the proof of v(x)=v(x).

Let v(x1) be the solution to

αv˜x1φ1x1+c0v˜x1p1v˜x1φ1x1=f˜x1φ1x1 in (ω,+)v˜(ω)=0,

where φ1(x1) is the density of 1-dimensional Gauss measure and ω is such that γ)=γ (Ω). By uniqueness v(x)=v˜x1 is the unique weak solution to Problem (4.2). Thus it remains to be proved the monotonicity. Since

1αx1+f˜(s)c0v(s)p1v(s)φ1(s)ds=v(x1)φ1(x1)forx1ω,

it is enough to show

(4.3) Ψ(x1):=x1+f˜(s)c0v(s)p1v(s)φ1(s)ds0forx1ω.

Suppose that Ψ(x1)<0 for some x1ω and consider x1ω,+ such that ΨX1=min[ω,+)Ψx1 . It is obvious that Ψ(x1)<0 . We have that X1>ω , otherwise it follows that v˜x1<0 in some neighborhood of ω, in contrast with v˜x10 in (ω, +∞) and v˜(ω)=0 .

In a similar way we show that there exists x1_ω,x1 such that Ψ(x1_)>0 . Indeed otherwise v(x1)0 in ω,X1 , in contrast with v(x1)0 in (ω, +∞) and v(ω)=0 .

Since Ψ(x1_)>0 there exists x1˜x1x1ˆ such that Ψ(x1˜)=0 and Ψ(x1)<0 in x1˜,x1ˆ and minx1˜,x1ˆΨ(x1)=Ψ(x1) . Then v˜x10 in x1˜,x1ˆ . As a consequence f˜c0vp1v is increasing in x1˜,x1ˆ , i.e. Ψ′(x1) is decreasing and Ψ(x1) is concave in x1˜,x1ˆ . Since Ψ(x1) has a minimum in x1˜,x1ˆ ), it follows that Ψ(x1) ≡ 0 in x1˜,x1ˆ , in contrast with Ψ(x1)<0 and Ψ(x1˜)=0 . This proves (4.3). □

Now we are in position to prove the following comparison result.

Theorem 9

Assume that (A0) and (A1′)-(A4′) hold. Let f be a nonnegative function, f˜L2logL1/2(Ω,γ) , let u and v be the nonnegative weak solution of (4.1) and (4.2), respectively. Then

(UV)+L(0,γ(Ω))1c0(FF˜)+L(0,γ(Ω)),

where

(4.4) U(s)=0su(t)pdtV(s)=0sv(t)pdtF(s)=0sf(t)dtF˜(s)=0sf˜(t)dt,

for s(0,γ(Ω)]andg(t), the decreasing rearrangement of g with respect to Gauss measure, is defined in (2.4). In particular, if we suppose that

F(s)F˜(s)foranys[0,γ(Ω)],

then

U(s)V(s)foranys[0,γ(Ω)].

Proof. We argue as in [16], [18]. Let us define the functions uκ,t:ΩR as

uκ,tx=0ifuxt,uxtsignuxift<uxt+κκsignuxift+κ<ux

for any fixed t and κ>0. Observing that uκ, t belongs to H01(Ω,γ), and ∇ uκ, t=χ{t<∣u∣⩽t+κ}u a.e. in Ω, function uκ, t can be chosen as test function in (18) and by (A3′) we get

1κt<|u|t+κ|u|2dγ+1κt<|u|t+κc|u|p1u(|u|t)sign(u)dγ+|u|>t+κc|u|p1usign(u)dγ1κt<|u|t+κf(|u|t)sign(u)dγ+|u|>t+κfsign(u)dγ.

In the standard way by (A5) we have

ddtu>tu2dγ|u|>t|f|dγ|u|>tc0up1usignu dγfor t>0.

By Hardy-Littlewood inequality (2.7), we obtain

ddtu>tu2dγ0γu(t)f(s)ds0γu(t)c0[u(s)]pdsfor t>0.

Using (2.1) by standard arguments (see [33]) it follows that

1γu(t)φ1Φ1γu(t)2F(γu(t))c0U(γu(t))for t>0.

Then

(4.5) u ( s ) 1 φ 1 Φ 1 ( s ) 2 F ( s ) c 0 U ( s )  for  s ( 0 , γ ( Ω ) ) .

By (4.4) the derivative of U equals

(4.6) U(s)=u(s)p for a.e.s(0,γ(Ω)).

Relations (4.6), (4.6) and (4.4) yield

(4.7) φ 1 Φ 1 s 2 d d s U ( s ) 1 p + c 0 U ( s ) F ( s ) for s ( 0 , γ ( Ω ) ) U ( 0 ) = 0 , U ( γ ( Ω ) ) = 0 .

Now let us consider problem (4.2). The solution v to problem (4.2) is unique and v(x)=v(x) (see Proposition 8).

By the properties of v we can repeat arguments used to prove (4.5) replacing all the inequalities by equalities and obtaining

(4.8) v ( s ) = 1 φ 1 Φ 1 s 2 F ~ ( s ) c 0 U ( s ) for s ( 0 , γ ( Ω ) ) ,

and thus

(4.9) φ 1 Φ 1 s 2 d d s V ( s ) 1 p + c 0 V ( s ) = F ~ ( s ) for s ( 0 , γ ( Ω ) ) V ( 0 ) = 0 , V ( γ ( Ω ) ) = 0.

Putting together (4.7) and (4.9) we get

(4.10) φ1Φ1(s)2ddsu(s)1p+ddsv(s)1pF(s)F˜(s)+c0(V(s)u(s))

Since U,VC([0,γ(Ω)]) , there exists s0 ∈ (0, γ (Ω)) such that

(UV)+L(0,γ(Ω))=1c0(UV)(s0).

We argue by absurdum. Suppose that

(UV)(s0)>1c0(FF˜)+L(0,γ(Ω)).

If s0<γ (Ω), by (4) it follows that

(4.11) F(s)F˜(s)+c0V(s)U(s)(FF˜)+L(0,γ(Ω))c0(UV)(s)<0fors(s0ε,s0+ε).

We set

Z=UVH2,(s0ε,s0+ε).

Then

(4.12) U(s)1pV(s)1p=Z(s)ρ(s),

where

(4.13) ρ ( s ) = 0 1 1 p τ U ( s ) + ( 1 τ ) V ( s ) 1 p 1 d τ > 0.

As a consequence of (4.10), (4.11), (4.12) and (4.13) we obtain

φ1Φ1(s)2ddsu(s)1p+ddsγ(s)1T=φ1Φ1(s)2h(s)ddsρ(s)Z(s)<0.

where

h ( s ) = 0 1 τ d d s ( U ( s ) 1 P ( 1 τ ) d d s V ( s ) 1 P d τ > 0.

We can conclude that

(4.14) ddsϱ(s)Z(s)<0fors(s0ε,s0+ε),

which is in contradiction with the assumption that Z has a maximum in s0.

If s0=γ (Ω), (4.14) holds for (γ (Ω)−ε, γ (Ω)), then Z′(γ (Ω))>0, but we know that Z′(γ (Ω))=0 and again a contradiction arises. □

Remark 10

Under the same assumption of Theorem 9, it is well-known that we deduce also that

uLrp(Ω,γ),vLrp(Ω,γ) for any1r.

Remark 11

As mentioned in the Introduction, when Ω is bounded the usual radially symmetrization method, when applied to an elliptic operator with a drift term as (1.2), modifies drastically the drift term in the symmetrized equation. For instance, we can apply Theorem 1 of [34] to equation (1.2), which can be formulated in divergence form as

Δ u ( x ) + div ( x u ) N u + c 0 u ( x ) p 1 u ( x ) = f ( x ) ,

so that in the notation of [34] we must take bi(x)=xi and c(x)=−N. Then the corresponding symmetrized problem built in [34] is

(4.15) Δ v ( y ) + B y y v ( y ) + B v div ( y y ) N v + c 0 v ( y ) p 1 v ( y ) = f # ( y ) in Ω # , v = 0 on Ω # ,

where Ω # is now a ball with the same volume than Ω, B=∥ x∥L(Ω), and f# is, for instance, the radially decreasing symmetric rearrangement of f. Notice that, in contrast with the “ artificial” first order terms arising in problem (4.5), the half-space Gaussian symmetrization problem (4.2) preserves the same type of drift than the original problem (1.2)

Using the Definition 1 the above comparison result can be extended to the case of Ω=ℝN and p > 1 under the assumptions of the previous Section.

Theorem 12

Let Ω=ℝN, p > 1 and the rest of conditions of Theorem 2. Let f be a nonnegative function and let f˜L2logL1/2(Hω,γ) for any ωR such that f˜=f˜ . Then

i) problem

(4.16) div(αv(x)φ(x))+c0|v(x)|p1v(x)φ(x)=f˜(x)φ(x) in RN

admits a unique weak solution v.

ii) let u and v be the nonnegative weak solution of (3.1) and of (4.16), respectively. Then, for any ε ∈ (0, 1)

(UV)+L(0,1ε))1c0(FF˜)+L(0,1ε),

where U,V,F and F˜ are defined as in (4.4) for s ∈ (0, 1). In particular, if we suppose that

F(s)F˜(s)for anys[0,1),

then

U(s)V(s)for anys[0,1).

Proof

Part i) is a consequence of Theorem 2 (see also [6]). To prove ii), as in the proof of Theorem 2, we first consider uM, the solution of the corresponding localized problem (P-M) on HM, and vM the solution of the symmetrized problem

div(αvφ)+c0|v|p1vφ(x)f˜(x)φ(x) in HMv0 on HM

where now HM=HMandf˜ is such that f˜=f˜ . We extend uM and vM by zero over ℝNHM and we denote again these extensions by uM and vM. Then, from the proof of Theorem 2 we know that {uM}, {vM} are bounded in H1(Hω+ω0,γ) with ωR and ω0 > 0. It follows that there exists u and v such that (up a subsequence) uM → u and vM → v weakly in H1(Hω) for any ωR , weakly in Lp+1(Hω, γ) for any ωR , strongly in Lq(Hω, γ) for any ωR with q < p+1 and a.e. in Hω for any ωR . Since the rearrangement application u → u is a contraction in Lr(Hω, γ) for any r=1, we get that uMu in Lq(Hω, γ) for any ωR with q < p+1 and a.e. in Hω for any ωR (and weakly in Lp+1(Hω, γ) for any ωR) . On the other hand, by the Polya-Sezgo theorem

uML2(HM,γ)uML2(HM,γ)

which implies (thanks to the assumption p > 1: Lemma 3) that uM is bounded in H1(Hω+ω0,γ) and thus uMu weakly in H1(Hω, γ) for any ωR . In particular, if we define

U M ( s ) = 0 s [ u M ( t ) ] p d t V M ( s ) = 0 s [ v M ( s ) ] p d t ,

we get that

(UMVM)+L(0,γ(HM))1c0(FF˜)+L(0,γ(HM)),

for any MN . Moreover UMU and VMV strongly on L(0, 1−ε) for any ε ∈ (0, 1) and thus we get the desired conclusion. □

Remark 13

Notice that we have proved the existence and, specially, the uniqueness of a solution of the problem

φ 1 Φ 1 s 2 d d s V ( s ) 1 p + c 0 V ( s ) = F ~ ( s ) for s ( 0 , 1 ) V ( 0 ) = 0 , V ( 1 ) = 0.

when we assume only 0F˜(s) and F˜Lloc1(0,1) , to be more precise F˜L1(0,1ε) for any ε ∈ (0, 1). For instance we could consider function of the type

F˜(s)=s(1s)α, for anyα>0.

This type of questions is related with the study of removable singularities for quasilinear equations (see, e.g. Section 5.2 of Veron [36]). In this theory, usually it is assumed N=2.

Remark 14

The above passing to the limit in M ∊ ℕ also holds (for very different arguments, see Remark 6) when p ≤ 1 once we assume that f ∊ L1(ℝN,𝛾) is in the dual space of H1(ℝN,𝛾) (which, essentially, corresponds to the case in which F ~ L 1 ( 0 , 1 ) .

We end this Section with a qualitative property for the case p<1 which holds as an application of the above comparison Theorem. First of all we recall that this assumption allows the formation of a free boundary in the sense that if f =0 over some suitable large subset of Ω, with

γ(xΩ:f(x)=0)=sf(0,γ(Ω)),

then the solution u of (4.1) have compact support on Ω (i.e., Nu:={xΩ:u(x)=0} , contained in {xΩ:f(x)=0} , is not empty) (see, e.g. [15]). Thus

(4.17) γ ( { x Ω : u ( x ) = 0 } ) = τ , for some τ 0 , s f

Notice that in terms of the corresponding function U(s) it means that U attaints its maximum on a subinterval [γ (Ω)-τ, γ (Ω)]. Solutions V(s) of the symmetrized problem (4.9) may have also this property (once the data F ~ ( s ) take its maximum on an interval γ(Ω)sF˜,γ(Ω) . This is possible since the diffusion operator of (4.9) becomes degenerate over the sets where V(s)0 , because p < 1 (see, Theorem 1.14 of [15}]). The following result gives some estimates about the decaying (in measure) of u(t) near the boundary of its support t=γ (Ω)-τ (notice that τ could be zero). Since our goal is of local nature we shall need some additional condition which holds, for instance, when f is a bounded function:

(4.18) uL(Ω)M, for someM>0.

Proposition 15

Assume that p < 1, (A2')-(A3') holds, f belongs to the dual space of H1(Ω,γ), f ≥ 0 and

(4.19) γ ( Ω ) < 1 a n d τ 0 o r Ω = R N and τ > 0.

Let u be the solution of (4.1) and assume (4.18). Let τ ∈ [ 0,sf] given by (4.17). Assume data f and Ω, and u be such that,

(4.20) U(γ(Ω)τδ)Muθδp+11p

for some δ ∈ (0,γ (Ω)-τ), and

(4.21) F(s) c0Mu+k(θ)Kδ(Ω)γ(Ω)τs+p+11pfors(γ(Ω)τδ,minγ(Ω)τ2,γ(Ω)),

where θ > 0 is some constant such that

(4.22) θ>Kδ(Ω)c0(1p)p+1p2p(p+1)1ppp1,
(4.23) Kδ(Ω)=1mins(γ(Ω)τδ,min(γ(Ω)τ2,γ(Ω))φ1Φ1s2,
k(θ)=θ1p2(p+1)1pp(1p)p+1pθKδ(Ω)c0

and

M u = max s [ 0 , γ ( Ω ) ] U ( s ) = U ( γ ( Ω ) ) = 0 γ ( Ω ) [ u ( t ) ] p d t = 0 γ ( Ω ) τ [ u ( t ) ] p d t = u p L 1 ( Ω : γ ) .

Then

s γ ( Ω ) τ [ u ( t ) ] p d t θ ( γ ( Ω ) τ s ) p + 1 1 p for any s ( γ ( Ω ) τ δ , γ ( Ω ) τ ) .

proof. Since ddsu(s)1p0u(s)1p=u(s) which is a decreasing function), for any δ >0 in a neighborhood of γ (Ω)-τ we have

(4.24) minsγ(Ω)τδ,minγ(Ω)τ2,γ(Ω)φ1Φ1s2ddsU(s)1pφ1Φ1s2ddsU(s)1p,forsγ(Ω)τδ,minγ(Ω)τ2,γ(Ω).

Notice that due to (4.19) then minsγ(Ω)τδ,minγ(Ω)τ2,γ(Ω)φΦ1(s)2>0 since minγ(Ω)τ2,γ(Ω)<1. Moreover, from (4.18)

0U(s)=[u(s)]pMp

which, in particular, implies

U(γ(Ω)τδ)Mp(γ(Ω)τδ).

Then, simplifying the notation K=Kδ (Ω) in (4.23), (4.7) and (4.24) we get

(4.25) ddsU(s)1p+Kc0U(s)KF(s)forsγ(Ω)τδ,minγ(Ω)τ2,γ(Ω),U(γ(Ω)τδ)Mp(γ(Ω)τδ),U(min(γ(Ω)τ2,γ(Ω)))=0.

When Ω =ℝN we recall that the existence of solutions can be proved by well-known methods since the perturbation is sublinear (see e.g. Theorem 4.2 of [15] and Remark 14).

Let us construct now a supersolution of (4.9). We define the function%

W(s)=Muη(γ(Ω)τs)ifs[γ(Ω)τδ,γ(Ω)τ],Muifs[γ(Ω)τ,min(γ(Ω)τ2,γ(Ω))],

where

η(r)=θrp+11p with θ satisfying (4.22).

Since p < 1, according Lemma 1.3 and Lemma 1.6 of [15] (where its conclusion implies that k(θ) > 0 when (4.22) holds), we get that

ddsW(s)1p+Kc0W(s)=Kc0Mu+k(θ)γ(Ω)τs+p+1p1fors0,minγ(Ω)τ2,γ(Ω),W(γ(Ω)τδ)=Muθδp+11p,W(min(γ(Ω)τ2,γ(Ω)))=0.

Notice that the support MuWˉ is the interval [γ(Ω)τδ,γ(Ω)τ] and that γ(Ω)τγ(Ω)sf .

From the assumption (4.20) U(γ(Ω)τδ)Wˉ(γ(Ω)τδ)) .

Moreover, by (4.21) we have

ddsU(s)1p+Kc0U(s)ddsW(s)1p+Kc0W(s) sγ(Ω)τδ,minγ(Ω)τ2,γ(Ω),U(γ(Ω)τδ)W(γ(Ω)τδ),U(min(γ(Ω)τ2,γ(Ω)))=W(min(γ(Ω)τ2,γ(Ω)))=0.

Thus, by the comparison principle,

U(s) W(s)for anys(γ(Ω)τδ,min(γ(Ω)τ2,γ(Ω))),

i.e.

0 s [ u ( t ) ] p d t 0 γ ( Ω ) τ [ u ( t ) ] p d t η ( γ ( Ω ) τ s )

and then

s γ ( Ω ) τ [ u ( t ) ] p d t η ( γ ( Ω ) τ s ) for any s ( γ ( Ω ) τ δ , γ ( Ω ) τ ) ,

which gives the result. □

Remark 16

The above result improves Proposition 5 of [17]. We send the reader to [15] and [17] for many other results concerning solutions with compact support and dead cores, when p < 1. In particular, it is well known that a suitable balance between the “sizes” of f and the set {x∈ Ω :f(x)=0} is needed for the occurrence of a free boundary: in some sense the last set must big enough. Such a balance appears here written in terms of the assumptions (4.20) and (4.21). Notice the above results says that if condition (4.20) holds for s=γ (Ω)-τ -δ then we get the decay inequality for any s∈(γ (Ω)-τ -δ, γ (Ω)-τ). Finally, notice that if in (4.25) there is an equality, instead an inequality, and if sf > 0 then, necessarily Mu = Mf, where

M f = F ( γ ( Ω ) ) = 0 γ ( Ω ) [ f ( t ) ] p d t = 0 γ ( Ω ) s f [ f ( t ) ] p d t = f p L 1 ( Ω : γ ) .

5 Comparison in mass for problems with a more general non linearity

The results of the previous section can be generalized to a class of elliptic problem with a more general zero order term. Several directions of improvement are possible. We could work with solutions outside the energy space, for instance when f(x)φ (x)∈ L1(Ω), as in the famous paper by Brezis and Strauss [10], but we prefer to continue working with solutions in the energy space and so, to fix ideas, we consider in this Section the following generalization

(5.1) i,j=1Nxjaij(x)uxi(x)xj+c(x)b(u(x))φ(x)=f(x)φ(x) in Ωu=0 on Ω.

We assume the structural assumptions (A0), A2)−(A4) and replace (A1) by

(B) b is a continuous increasing function such that b(0)=0 and b(u)u > 0

Moreover arguing as in Theorem 9 it is possible to prove a comparison result between the concentration of the solution u to problem (5.1) and the solution vH01Ω,γ to the following problem

(5.2) div(αv(x)φ(x))+c0b(v(x))φ(x)=f˜(x)φ(x) in Ωv=0 on Ω,

where Ω is defined in (2.6) and f˜=f˜ , the Gauss rearrangement of f˜ .

Theorem 17

Suppose that (A0), (A2)−(A4) and (B) hold. Let f be a nonnegative function, f˜L2logL1/2Ω,γ and let u and v be the nonnegative weak solution of (5.1) and (5.2), respectively. Then

( U V ) + L ( 0 , γ ( Ω ) ) 1 c 0 ( F F ~ ) + L ( 0 , γ ( Ω ) ) ,

where

U ( s ) = 0 s b u ( t ) d t V ( s ) = 0 s b v ( s ) d t F ( s ) = 0 s f ( t ) d t F ~ ( s ) = 0 s f ~ ( t ) d t ,

for s∈(0,γ (Ω)].

The proof of Theorem 17 runs as in the case b(u)=∣u∣p-1 u, but as a preliminary step we need that the analogue of Proposition 8 is in force. For reader convenience we detail the following result of existence.

Proposition 18

Suppose that (A0), (A2)−(A4) and (B) hold. If f is nonnegative, then Problem (5.1) has a unique nonnegative weak solution uH01(Ω,γ) ,i.e. such that c(x) b(u)∈ L1 (Ω, γ) and

Ω i , j = 1 N a i j u x i ψ x j d x + Ω c b ( u ) ψ d γ = Ω f ψ d γ

for every ψH01(Ω,γ)L(Ω) holds. Moreover c(x) b(u)u∈ L1(Ω, γ).

Proof. We give only some details about existence, because the proof of positivity and uniqueness is standards and runs using the monotonicity of b. We introduce the following class of approximated problems:

(5.3) i,j=1Nxjaij(x)ukxi+Tkcbukφ(x)=f(x)φ(x) in Ωuk=0 on Ω,

where Tk(s) is defined as in (3.5). Since ∣Tk(c(x) b(uk)) ∣φ (x) ⩽ kφ (x) and Tk(c(x) b(uk)) uk⩾0, the existence of a variational weak solution uk∈ H01(Ω,γ) is well-known (see, e.g. [9]). Taking uk as test function and using Log-Sobolev inequality (2.10) we obtain

ukL2(Ω,γ)CfL2logL1/2(Ω,γ)

and

Ω T k c ( x ) b ( u k ) u k d γ C f L 2 log L 1 / 2 ( Ω , γ )

for some positive constant C independent of uk. Then the sequence uk is bounded in H01(Ω,γ), then there exists a function uH01(Ω,γ) such that (up a subsequence

u k u in H 0 1 ( Ω , γ )  and u k u a.e. in Ω

hold. In particular

Tkc(x)b(uk)ukc(x)b(u)ua.e. inΩ.

By Fatou’s Lemma and estimate (5) we get

Ω c ( x ) b ( u ) u d γ lim inf Ω T k c ( x ) b ( u k ) u k d γ C f L 2 log L 1 / 2 ( Ω , γ ) ,

then c(x)b(u)uL1(Ω,γ). Moreover for some δ > 0 and every E⊂ Ω by (5) we get

E T k c ( x ) b u k d γ = E u k < 1 / δ T k c ( x ) b u k d γ + E u k > 1 / δ T k c ( x ) b u k d γ b 1 δ E c ( x ) d γ + δ C f L 2 log L 1 / 2 ( Ω , γ ) .

Choosing δ=Ec(x)dγ if sup b(s) < +∞ or otherwise δ=1b11Ec(x)dγ , we get the equintegrability and Vitali’s Theorem allow us to conclude that

(5.4) T k c ( x ) b ( u k ) c ( x ) b ( u ) in L 1 ( Ω , γ ) .

Now we are able to pass to the limit in (5.3) for every ψ∈ H01(Ω,γ)∩L(Ω) and the result holds. □

Remark 19

Theorem 17 also holds if we assume in (B) that b is merely non−decreasing b(0)=0 and b(u)u>0. The only difficulty arises when dealing with b-1 because now is not necessarily a function but a maximal monotone graph of ℝ2 and some technicalities are needed (see, e.g., [10], [15] and [35]).

Remark 20

A different extension concerns the case in which we replace f by a general datum F=f-divg with f that satisfy (A4) and g∈(L2(Ω,γ))N. To have nonnegative solutions we have to require < F, ψ >≥0 for every nonnegative test function.

We can also compare (in the sense of rearrangements) problems with different nonlinearities. Just to give an idea, let us consider problem (5.1) when the domain Ω is Hω, the half−space x1 > ω with ω ∈ ℝ. We take into account two smooth strictly increasing functions b and b˜ having the same domain such that b(0)= b˜ (0)=0, and two positive increasing functions of x1 variable f and f˜ defined in Hω. Recalling the symmetrized problem (4.5) it is natural to require some conditions on the inverse of the zero order term functions. Indeed let us assume that b and b˜ are smooth functions such that

(5.5) ( ( b ~ ) 1 ) ( s ) b 1 ( s ) for every s R ,

where b-1 and ( b˜ )-1 the inverse functions of b and b˜ respectively and that the datum f is “ less concentrated” than the datum f˜ , namely

H ν f ( x ) d x H ν f ~ ( x ) d x for every ν > ω .

Then, we are going to prove that

(5.6) H ν b ( u ( x ) ) d x H ν b ~ u ~ ( x ) d x for every ν > ω ,

where u is the rearrangement with respect to Gauss measure of the solution u to problem (5.1) and ũ is the solution to the following problem

div(αu˜)+b˜(u˜)φ(x)=f˜(x)φ(x) in Hωu˜=0 on Hω.

We refer to [35] for unweighted case φ (x) ≡ 1. A more general result, implying conclusion (5.6) can be proved. To be more precise, let b1, b2 be two continuous non decreasing functions. We say that b1 is weaker than b2, and we write

(5.7) b 1 b 2 ,

if they have the same domain of definition, and there exists a contraction ρ :ℝ → ℝ (i.e. such that ∣ ρ (a)-ρ (b)∣ ⩽ ∣ a-b∣ for a,b∈ ℝ) and b1=ρb2 (notice that this implies condition (5.5) when they are differentiable). We are now in position to state a comparison result between the concentration of the solution uH01(Ω) to problem (5.1) with c(x) ≡ 1 (for simplicity) and the solution vH01,γ) to the following problem

(5.8) div(αv(x)φ(x))+b˜(v(x))φ(x)=f˜(x)φ(x) in Ωv=0 on Ω.

where Ω is defined in (2.6), f˜ = f˜ and ( b˜ )-1≺ b-1.

Theorem 21

Suppose c(x)≡ 1, (A0), (A2)−(A4) and (B) hold with c0≡ 1 and ( b˜ )-1≺ b-1. Let f be a nonnegative function, f˜ ∈ L2log L-1/2,γ) and let u and v be the weak nonnegative solution of (5.1) and (5.8), respectively. Then we get

(BB˜)+L(0,γ(Ω))(FF˜)+L(0,γ(Ω)),

where

B ( s ) = 0 s b u ( t ) d t B ~ ( s ) = 0 s b ~ w ( t ) d t F ( s ) = 0 s f ( t ) d t F ~ ( s ) = 0 s f ~ ( t ) d t

for s∈(0,γ (Ω)].

Proof. By using the Yosida approximation of functions ( b˜ )-1 and b-1 it is enough to prove the conclusion when both functions are differentiable and strictly increasing (see, e.g. [10], [35]). As in the proof of Theorem 9 we get

φ1Φ1(s)2ddsb1B(s)+c0B(s)F(s) for s(0,γ(Ω))B(0)=0,B(γ(Ω))=0,

and

φ1Φ1(s)2dds(b˜)1B˜(s)+c0B˜(s)=F˜(s) for s(0,γ(Ω))B˜(0)=0,B˜(γ(Ω))=0.

Assume that (BB˜)+L(0,γ(Ω))>0 (otherwise the conclusion is trivial). Since B,B˜C0[0,γ(Ω)] the above norm is attainted in some point s0∈ (0,γ (Ω)] (is clear that s0 > 0), so that

(BB˜)s0=1C0(BB˜)+L(0,γ(Ω)).

On the other hand, since ( b˜ )-1 and b-1 are differentiable and strictly increasing we get that B and B˜ are convex functions on (0,γ (Ω)], from the assumption (5.7) we get that

φ Φ 1 s 2 d d s ( b ) 1 B ~ ( s ) + c 0 B ~ ( s ) F ~ ( s ) .

Then we can reproduce the final arguments of the proof of Theorem 9 and the result holds. □

Example 22

Condition (5.7) holds, for instance, if b(u)=eα u -1 and b˜ (u)=eβ u -1 with β ⩾ α>0. It also holds for b(u)=uα when b˜(u)=uα if 0u<1uβ if u1withβα>0.

Remark 23

The pointwise comparison between b(u(x)) and b˜ (ũ(x)) usually fails. This type of pointwise comparison was studied in [2] for the case of some evolution problems which are related with problem (5.1) through its implicit time discretization.

Remark 24

Proposition 15 can be extended to the case of a function b(u) more general than ∣u∣p-1u with p < 1. The condition p < 1 is now replaced by a condition stated in terms of an improper integral

0 τ d s σ 1 ( c 0 2 s 2 ) < + , f o r a n y τ ( 0 , 1 ) ,

where σ(r)=0rb1(s)sds (see Lemma 1.3 of [15]).

Remark 25

Theorem 2 can be also extended to the structural assumptions of this Section when Ω =ℝN by replacing the expression ∣u∣p+1 by b(u)u and by working in the Orlicz space LlocA(ℝN, γ), where A(t)=b(t)t and by asking some additional conditions. We recall that b verifies a Δ2 condition, i.e. there exist a constant K and s0 such that

b ( 2 s ) K b ( s ) s > s 0 .

We stress that all estimates in Lemma 3 holds replacing ∣u∣p-1 u with b(u), when

b ( k u ) k u | u | p + 1 for u > u 0

for some k,u0 > 0 and for some p > 1 and the only crucial step is the weak convergence in the Orlicz space LlocA(ℝN, γ). Clearly we have to require more on b in order to have that A is an N-function (see [1]). For example b has to be an odd function. Moreover when b verifies a Δ2 condition, it is easy to check that A does. Then the Orlicz space LlocA(ℝN,γ) is reflexive and the boundedness of UMLlocARN,γ allows as to pass to the limit in the sequence of approximate problems.

For some results in this framework but with the Lebesgue measure see [28] and its references. For other generalizations of Brezis result [8] see for instance [14], [7], [6], [28].

Acknowledgement

The research of J.I. Díaz was partially supported by the project ref. MTM2017-85449-P of the DGISPI (Spain) and the Research Group MOMAT (Ref. 910480) of the UCM. M.R. Posteraro was supported by Italian MIUR through research project PRIN 2015 "Partial differential equations and related analyticgeometric inequalities" and by Gruppo Nazionale per l Analisi Matematica, la Probabilitá e le loro Applicazioni (GNAMPA) of Istituto Nazionale di Alta Matematica (INdAM). F. Feo was partially supported by Gruppo Nazionale per l Analisi Matematica, la Probabilitá e le loro Applicazioni (GNAMPA) of Istituto Nazionale di Alta Matematica (INdAM). This paper has partially done during the visits of the second and the third authors to UCM in Madrid. Hospitality and support of this institution is gratefully acknowledged. J.I. Diaz was an Editor of the ANONA although had no involvement in the final decision

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Received: 2020-10-02
Accepted: 2021-01-09
Published Online: 2021-04-14

© 2021 J. I. Díaz et al., published by De Gruyter

This work is licensed under the Creative Commons Attribution 4.0 International License.

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