RETRACTED ARTICLE: Boundary value behaviors for solutions of the equilibrium equations with angular velocity

This work is concerned with a mixed boundary value problems for the slow equilibrium equations with prescribed angular velocity. As an application, we find sufficient conditions for the existence and uniqueness of blow-up solutions under weaker conditions.


Introduction
In -D space, the equilibrium equations for a self-gravitating fluid rotating about the x  axis with prescribed velocity (r) can be written as ∇P = ρ∇(-+ r  s  (s) ds), = πgρ. (.) Here ρ, g, and denote the density, gravitational constant, and gravitational potential, respectively, P is the pressure of the fluid at a point x ∈ R  , and r = x   + x   . We want to find axisymmetric equilibria and therefore always assume that ρ(x) = ρ(r, x  ).
For the density ρ, from (.)  we can obtain the induced potential Obviously, ρ is decreasing when ρ is increasing.
In the study of this model, Auchmuty A standard method to obtain steady states is prescribing the minimizer of the stellar energy functional. The main problem is to show that the steady state has finite mass and compact support. To approach this problem, we define the energy functional Here In this paper, we assume that J(r) is nonnegative, continuous, and bounded on [, +∞) and P is nonnegative, continuous, and strictly increasing for s >  and satisfies: In Section , first we prove the existence of a minimizer of the energy functional F in A M . Then we give the properties of minimizers; they are stationary solutions of equation (.) with finite mass and compact support. The main difficulty in the proof is the loss of compactness due to the unboundedness of R  . To prevent the mass from running off to spatial infinity along a minimizing sequence, our variational approach is related to the concentration-compactness principle due to Fang and Li []. For many other interesting results, see references [-].
Throughout this paper, for simplicity of presentation, we use to denote R  and use · p to denote · L p (R  ) . Define We denote by C a generic positive constant and by χ the indicator function.

Minimizer of the energy
In this section, we present some properties of the functional F and prove the existence of a minimizer. It is easy to verify that the function F is invariant under any vertical shift, that First, we give some estimates.

R E T R
The proof can be found in [].
From the above estimates we can complete our proof.
The mappings A M → A M , ρ → ρ, J → J are all one-to-one and onto, which completes our proof.
From Lemma . we immediately obtain that any minimizing sequence (ρ n ) ∈ A M of F satisfies be bounded in L / (R  ) and ρ n ρ  weakly in L / (R  ). Then, for any R > , Proof By Sobolev theorem and Lemma . we can complete the proof.
Lemma . Assume that P  holds. Let (ρ n ) ∞ n= ⊂ A M be a minimizing sequence of F(ρ). Then there exist a sequence (a n ) ∞ n= ⊂ R  and δ  > , R  >  such that for all sufficiently large n ∈ N.
Proof Split the potential energy: From Lemma . we easily see that I  ≤ C R . The estimates for I  and I  are straightforward: We know that F pot (ρ n ) <  from (.). Thus, when R large enough, -F pot >  dominates the sign of (.), so that there exist δ  > , R  >  as required.
We are now ready to show the existence of a minimizer of h M , provided that P  holds.
Theorem . Assume that P  holds. Let (ρ n ) ∈ A M be a minimizing sequence of F. Then there exist a subsequence, still denoted by (ρ n ), and a sequence of translations Tρ n := ρ n (· + a n e  ) with constant a n and e  = (, , ) such that and Tρ n ρ  weakly in L   (R  ). For the induced potentials, we have ∇ Tρ n → ∇ ρ  strongly in L  (R  ).

A R T I C L E
Remark . Without admitting the spatial shifts, the assertion of the theorem is false: Given a minimizer ρ  and a sequence of shift vectors (a n e  ) ∈ R  , the functional F is translation invariant, that is, F(Tρ) = F(ρ). But if |a n e  | → ∞, then this minimizing sequence converges weakly to zero, which is not in A M .
Proof Split ρ ∈ A M into three different parts: Thus, If we choose R  > R  , then Next we estimate I  and I  : where l = ρ l . Denote M l = ρ l , l = , , . Then M = M  + M  + M  . Using the above estimates and Lemma ., we have where C  , C  are positive and depend on M but not on R  or R  . Let (ρ n ) ∈ A M be a minimizing sequence and (a n e  ) ∈ R  such that Lemma . holds. Since F is translation invariant, the sequence (Tρ n ) is a minimizing sequence too. So, ||Tρ n ||  ≤ M. Thus, there exists a subsequence, denoted by (Tρ n ) again, such that Tρ n ρ  weakly in L   (R  ). By Mazur's lemma and Fatou's lemma, Now we want to show that Due to Lemma ., ∇ Tρ n, +Tρ n, converge strongly in L  (B R  ). Therefore, we only need to show that for any ε > , By Lemmas . and . it suffices to prove that Tρ n, dx < ε.
(  .  ) Choosing R  < R  , we obtain that M n, ≥ δ  for n large enough from Lemma .. By (.) we have where n,l is the potential induced by Tρ n,l , which in turn has mass M n,l , n ∈ N ∪ {}, and the index l = , ,  refers to the splitting. Given any ε > , by Lemma . we can increase R  > R  so that C  ∇ ,  < ε/. Next, choose R  > R  such that the first term in (.) is less than ε/. Now, since R  and R  are fixed, the third term converges to zero by Lemma .. Since (Tρ n ) is a minimizing sequence, we have |F(Tρ n )h M | < ε/ for suitable n. So, for n large enough, Since Tρ n ρ  weakly in L  (R N ), it follows that for any ε > , there exists R >  such that thus, so thatρ  ∈ A M . Together with (.), we obtain The proof is completed.
Next, we show that the minimizers obtained are steady states of equation (.).

be a minimizer of F(ρ) with induced potential  . Then
where K  is a constant. Furthermore, ρ  satisfies (.).
Proof We will derive the Euler-Lagrange equation for the variational problem. Let ρ  ∈ A M be a minimizer with induced potential  . For any > , we define For a test function ω ∈ L ∞ (R  ) that has compact support and is nonnegative on V c , define where τ ≥  is small such that Therefore, ρ τ ∈ A M . Since ρ  is a minimizer of F(ρ), we have Hence, This holds for all test functions ω positive and negative on V as specified above; hence, for all >  small enough, Q (ρ  ) -J(r) +  = K on V , and Q (ρ  ) -J(r) +  ≥ K on V c , (  .  ) where K is a constant. Taking the limit as → , we get Q (ρ  ) -J(r) +  = K  on the support of ρ  . (  .   ) By taking the gradient of both sides of (.) we can prove that ρ  satisfies the equilibrium equation (.).