The lowest $T=2\mathrm{}$ state in ${}_{}{}^{44}{}_{}{}^{}\mathrm{Ti}$ has been found in the reaction ${}_{}{}^{40}{}_{}{}^{}\mathrm{Ca}(\alpha ,\gamma ){}_{}{}^{44}{}_{}{}^{}\mathrm{Ti}$ at an excitation energy of 9338 ± 2 keV in ${}_{}{}^{44}{}_{}{}^{}\mathrm{Ti}$. The radiative yield has been measured and the $\gamma$ decay has been studied.

• Received 21 September 1972

DOI:https://doi.org/10.1103/PhysRevLett.29.1472