Excited states of the ${}^{93}\mathrm{Nb}$ nucleus are produced through the fusion-evaporation reactions ${}^{82}\mathrm{Se}({}^{14}\mathrm{N},3n){}^{93}\mathrm{Nb}$ and ${}^{82}\mathrm{Se}({}^{16}\mathrm{O},1p4n){}^{93}\mathrm{Nb}$. On the basis of new experimental data, the previously known level scheme is extended. Level structure is discussed in comparison to a shell-model calculation. The calculation results demonstrate that the low-lying states can be interpreted as the excitation of the protons from the $1p_{1/2}$ orbit, through the $Z=40$ subshell closure, to the $0g_{9/2}$ orbit. The moderate-spin states involve not only the proton excitation through the $Z=38$ or 40 subshell ($0f_{5/2}1p_{3/2}1p_{1/2}\to 0g_{9/2}$), but also the neutron excitation through the $N=56$ subshell ($1d_{5/2}\to 0g_{7/2}$). For the high-spin states above 9.1 MeV, the neutron excitation across the $N=50$ closed shell plays a dominant role.

• Received 6 November 2021
• Revised 19 January 2022
• Accepted 14 March 2022

DOI:https://doi.org/10.1103/PhysRevC.105.034344