Multiscale modeling of composite cylindrical tank

This article provides the useful data information on multiscale modeling of liquid storage laminated composite cylindrical tank under seismic load. The investigation process is divided into three levels. Within the numerical homogenization, the hexagonal microstructure one-eighth and full RVE model is assumed on micro-scale level. Homogenization of unidirectional lamina is done in four steps. For effective material properties of the whole laminate, the laminated representative volume element is assumed on meso-scale level. The numerical homogenization is done by using the Finite Element Method in the program ANSYS. Effective modulus of elasticity is taken into the calculation of internal forces of the laminated composite cylindrical tank on macro-scale level. The base shears bottom of tank wall and tank base, the bending moment above the base plate, and overturning moment bellow the base plate as function of the tank fluid filling are presented. Data inform about seismic response of liquid laminated composite tank during seismic even in Slovak Republic, respecting of Eurocode 8 recommendations.


Subject area
Applied Mechanics More specific subject area Mechanics of Composite Materials, Fluid Dynamics Type of data Text file, graph, figure How data was acquired ANSYS software, Eurocode 8 -Design of structure for earthquake resistance -Part. 4 1. Data

Data on micro-scale level
On the micro-scale level, the material properties of one laminated composite layer are obtained for an unidirectional fiber reinforced composite layer consists of isotropic fibers and isotropic matrix. The fiber volume fraction and fiber diameter were found from electron microscope digital shot. Each layer of the laminate has the same thickness. The material properties of each layer were used from obtained average stresses [1,2].

Data on meso-scale level
The circular cylindrical tank is made of the laminate [0/0/90/90] NS , where N ¼20 for the wall and for the base slab. The effective material properties of the whole laminate are observed from mesoscale level [1].

Data on macro-scale level
Then, these material properties are used for calculation of internal forces of laminated composite ground supported cylindrical tank [1,3,4]. The reservoir is filled with water. The container is without a roof slab. We consider only horizontal seismic load. A used elastic response spectrum is determined for the Slovak Republic, a g ¼1.5 m s −2 , B category of the subsoil. The seismic response data of fluid filled laminated composite cylindrical tank was obtained.

Experimental design, materials and methods
For heterogeneous materials, a large number of material properties are needed [5]. The values of these properties change as a function of the volume fraction of reinforcement. An alternative to the experimental determination of these properties is an usage of homogenization techniques on representative volume element (RVE) [6][7][8][9].
Within the numerical homogenization, the hexagonal microstructure was assumed. Four steps of numerical homogenization of unidirectional lamina were applied: Step 1 In order to determine the components C i1 with i¼ 1, 2, 3, (z, x, y), the strain ε 0 1 ¼ 1 is applied to stretch the RVE in the fiber direction x 1 . The coefficients C i1 are found by using C i1 ¼ σ i . Fig. 1 presents contour plot of stresses on deformed RVE under application of the strain ε 0 In order to determine the components C i2 with i¼ 1, 2, 3, (z, x, y), the strain ε 0 2 ¼ 1 is applied to stretch the RVE in the fiber direction x 2 . The coefficients C i2 are found by using C i2 ¼ σ i . Fig. 2 presents contour plot of stresses on deformed RVE under application of the strain ε 0 2 ¼ 1.
Step 3 In order to determine the components C i3 with i¼ 1, 2, 3, (z, x, y), the strain ε 0 3 ¼ 1 is applied to stretch the RVE in the fiber direction x 3 . The coefficients C i3 are found by using C i3 ¼ σ i . Fig. 3 presents contour plot of stresses on deformed RVE under application of the strain ε 0 3 ¼ 1.
The coefficients C 55 and C 66 are found by using C 55 ¼ τ yz and C 66 ¼ τ xz .