Abstract
We prove the consistency of tiltan with the positive relation \(\omega ^*\cdot \omega _1 \rightarrow (\omega ^*\cdot \omega _1,\text {infinite path})^2\).
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Notes
Let us indicate that in some good old manuscripts the pronunciation is taltan see the relevant discussion in [14].
We may assume, without loss of generality, that \(S\times {A}\subseteq {V}\).
By a careful choice of A we may assume that \(t_m\ne t_{m+1}\).
The adjective linked means that any two elements from \(A_\beta \cup A_\gamma \) are compatible.
Recall that tiltan with the continuum hypothesis imply diamond.
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Garti, S. Tiltan and graphs with no infinite paths. Period Math Hung 88, 137–147 (2024). https://doi.org/10.1007/s10998-023-00544-3
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DOI: https://doi.org/10.1007/s10998-023-00544-3