Abstract
In this paper we obtain necessary and sufficient conditions in order that a linear operator, acting in spaces of measurable functions, should admit an integral representation. We give here the fundamental results. Let (Ti,μ i) (i=1,2) be spaces of finite measure, and let (T,μ) be the product of these spaces. Let E be an ideal in the space S(T1,μ 1) of measurable functions (i.e., from |e1|⩽|e2|, e1∈ S (T1,μ 1), e2∈E it follows that e1∈E). THEOREM 2. Let U be a linear operator from E into S(T2,μ 2). The following statements are equivalent: 1) there exists aμ-measurable kernel K(t,S) such that (Ue)(S)=∫K(t,S) e(t)dμ(t) (e∈E); 2) if 0⩽en⩽∈E (n=1,2,...) and en→0 in measure, then (Uen)(S) →0μ 2 a.e. THEOREM 3. Assume that the function Ф(t,S) is such that for any e∈E and for s a.e., theμ 2-measurable function Y(S)=∫Ф(t,S)e(t)dμ 1(t) is defined. Then there exists aμ-measurable function K(t,S) such that for any e∈E we have ∫Ф(t,S)e(t)dμ 1(t)=∫K(t,S)e(t)dμ 1(t)μ 1a.e.
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Translated from Zapiski Nauchnykh Seminarov Leningradskogo Otdeleniya Matematicheskogo Instituta im. V. A. Steklova AN SSSR, Vol. 47, pp. 5–14, 1974.
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Bukhvalov, A.V. Integral representation of linear operators. J Math Sci 9, 129–137 (1978). https://doi.org/10.1007/BF01578539
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DOI: https://doi.org/10.1007/BF01578539