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Exactly k MSTs: How Many Vertices Suffice?

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Combinatorial Optimization and Applications (COCOA 2023)

Abstract

In this work, we study the problem of finding a weighted graph with exactly k minimum spanning trees (MSTs, in short) while minimizing the number of vertices. While finding a graph with k MSTs is easy, finding such a graph with the minimum number of vertices remains an interesting open problem. Recently, Stong [15] proved an upper bound within \(\log k\) multiplicative factor of the minimum. In this work, we prove the following results which make further progress on this problem:

  1. 1.

    Large weights do not help in constructing a minimal weighted graph with prime number of spanning trees.

  2. 2.

    For \(n\ge 6\) and \(1 \le k \le n^2\), n vertices suffice for constructing a graph with k spanning trees.

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Correspondence to Anuj Tawari .

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Dutta, A., Muthu, R., Tawari, A., Sunitha, V. (2024). Exactly k MSTs: How Many Vertices Suffice?. In: Wu, W., Guo, J. (eds) Combinatorial Optimization and Applications. COCOA 2023. Lecture Notes in Computer Science, vol 14461. Springer, Cham. https://doi.org/10.1007/978-3-031-49611-0_7

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  • DOI: https://doi.org/10.1007/978-3-031-49611-0_7

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