The nuclide ${}^{262}\mathrm{Db}\hspace{0.5em}\mathrm{}(Z=105\mathrm{})\mathrm{}$ was produced in the reaction ${}^{248}\mathrm{Cm}{(}^{19}\mathrm{F},\hspace{0.5em}5n)$ at a beam energy of 106.5 MeV. ${}^{262}\mathrm{Db}$ was identified by observing four time correlated $\alpha$-$\alpha$ decay chains of ${}^{262}\mathrm{Db}$ and its daughter ${}^{258}\mathrm{Lr}$. From these correlations a production cross section of ${0.26}_{-0.09}^{+0.15\mathrm{}}$ nb was deduced. This cross section is more than one order of magnitude smaller than the peak cross section observed in the ${}^{249}\mathrm{Bk}{(}^{18}\mathrm{O},\hspace{0.5em}{5n)}^{262}\mathrm{Db}$ reaction. Model calculations with the HIVAP code gave good agreement with the cross section measured in the ${}^{19}\mathrm{F}{+}^{248}\mathrm{Cm}$ reaction.

• Received 20 January 1999

DOI:https://doi.org/10.1103/PhysRevC.59.3433