Elsevier

Applied Mathematics and Computation

Volume 268, 1 October 2015, Pages 1282-1291
Applied Mathematics and Computation

Solvability and spectral properties of the boundary value problem for degenerating higher order parabolic equation

https://doi.org/10.1016/j.amc.2015.06.131Get rights and content

Abstract

In the present paper we study the boundary value problem for degenerating higher order parabolic equation. A priori estimate for the solution of the boundary value problem is obtained. The existence of unique regular and strong solutions of the problem is proved. The adjoint problem is also investigated.

Introduction

Many problems of heat conductivity, chemical kinetics, burning and thermal explosion are described by the parabolic equations. Boundary value problems for non-degenerating parabolic equations are investigated in works of Friedman [1], Browder [2], Mikhaylov [3], Il’in et al. [4], Gorenflo and Mainardi [5], Luchko [6], [7] and others. Degenerating elliptic and parabolic equations are studied by Il’in [8], [9], [10]. In work of Baouendi and Grisvard [11] the problem of finding a solution of the equation 2kux2k+(1)kxut=fin domain Ω ⊂ (a < x < b) × (0 < t < T), a < 0 < b, satisfying the boundary conditions luxl=0,l=0,1,,k1, on x=a,x=b and the initial conditions u(x,0)=u0(x),0<x<b,u(x,T)=uT(x),a<x<0is considered, where k is positive integer. The authors proved that if x12u0(x)L2(0,b),|x12|uT(x)L2(a,0),fL2([0,T],Hk), then there exists a unique solution u(x,t)L2([0,T],Hk0)

This equation is parabolic equation with changing direction of time. The boundary value problems for such equations were studied in Tersenov’s monography [12].

In the present article we consider the equation Lu=f(x,t),where Lu(tm2kx2k+(1)kt)u,m is a positive number and k ≥ 1 is fixed integer. Below in Section 2 for Eq. (1.1) we study the boundary value problem in the domain Ω={(x,t):0<x<p,0<t<T}. An inequality which we use at the proof of a priori estimate in the norm of the space W2,mk,0(Ω) for the solution of the problem is proved. Existence of unique regular and strong solutions of the problem and its continuous dependence on f(x, t) is proved. It is established that the spectrum of the problem is empty set. It is shown that the problem is Volterra property. The adjoint problem is also investigated.

Section snippets

Statement of the problem

Problem 1

Find the solution u(x, t) of Eq. (1.1) in the domain Ω satisfying conditions 2lux2l(0,t)=2lux2l(p,t)=0,l=0,1,,k1,0tT,u(x,0)=0,0xp.Let V(Ω)={u:uCx,t2k1,0(Ω¯),2kux2k,utC(Ω)L2(Ω)andconditions(2.1),and(2.2)aretrue},W(Ω)={f:fCx,t2k,0(Ω¯),2k+1ux2k+1L2(Ω),2lfx2l(0,t)=2lfx2l(p,t)=0,l=0,1,,k}.

We define the operator L Lu(tm2kx2k+(1)kt)umapping the set V(Ω) into C(Ω). The closure of the operator L in L2(Ω) we denote by L¯.

Definition 2.1

The function u(x, t) ∈ V(Ω) is called the regular

A priori estimate of the solution

The following holds

Lemma 3.1

For any n, 1 ≤ nk and any function u(x, t) ∈ V(Ω) the following inequality is true tm2knnuxnL2(Ω)212(tm2k(n1)n1uxn1L2(Ω)2+tm2k(n+1)n+1uxn+1L2(Ω)2).

Proof

According to the definition of the norm in L2(Ω) we have tm2knnuxnL2(Ω)2=0T[0ptm2k(n+1)nuxntm2k(n1)x(n1uxn1)dx]dt.Integrating the interior integral by parts with respect to x and taking into account (2.1), and (2.2) we get tm2knnuxnL2(Ω)2=0T0p(tm2k(n+1)n+1uxn+1)tm2k(n1)n1uxn1dxdt.

The regular solvability of Problem 1

We search a regular solution of Problem 1 in the form of the Fourier series u(x,t)=n=1un(t)Xn(x)expanded in complete orthonormal system Xn(x)=2psinλnx,λn=πnp,nNin L2(0, p).

It is clear that the function u(x, t) satisfies condition (2.1). Let fW(Ω). We expand the function f(x, t) into the Fourier series in functions Xn(x) f(x,t)=n=1fn(t)Xn(x),where fn(t)=0pf(x,t)Xn(x)dx,n=1,2,.

Substituting (4.1) and (4.2) into Eq. (1.1) we obtain the following equation for unknown function un(t) un(t)+λ

The strong solvability

Substituting (4.5) into (4.1) we get u(x,t)=0p0tK(x,t;ξ,τ)f(ξ,τ)dξdτwhere K(x,t;ξ,τ)=n=1Xn(x)Xn(ξ)exp{λn2ktm+1τm+1m+1}dτ.The following is true:

Theorem 5.1

For any fL2(Ω) the unique strong solution of Problem 1 exists, continuously depends on f(x, t), satisfies the estimation (3.4) and it can be represented in the form (5.1).

Proof

Let f be an arbitrary function in L2(Ω). From relation C0(Ω)W(Ω)L2(Ω) follows that W(Ω) is dense in L2(Ω). Then there exists a sequence {fi} ⊂ W(Ω), iN such that fifL

Spectrum of Problem 1

Definition 6.1

The spectrum of the problem is the set of eigenvalues of the operator L¯ of Problem 1.

Definition 6.2

[15]. A problem is called the Volterra property if the inverse operator of the problem is Volterra property.

Theorem 6.1

The spectrum of Problem 1 is the empty set.

Proof

From (3.4) and (5.1) we conclude that it is the defined operator L1 on W(Ω) which is the inverse of the operator L and acts from W(Ω) to V(Ω) by the rule (L1f)(x,t)=0p0TK¯(x,t;ξ,τ)f(ξ,τ)dτdξ,where K¯(x,t;ξ,τ)=θ(tτ)K(x,t;ξ,τ),θ(t)=1fort>0andθ(t)=0fort0.

The adjoint problem

We consider the equation L*υ=g(x,t),where L*υ(tm2kx2k(1)kt)υ.

Problem 1*

Find the solution υ(x,t) of Eq. (7.1) in the domain Ω satisfying the conditions 2lυ(0,t)x2l=2lυ(p,t)x2l=0,l=0,1,2,,k1;0tTυ(x,T)=0,0xp.We denote by V*(Ω)={υ(x,t):υCx,t2k1,0(Ω¯)Cx,t2k,1(Ω),υt,2kυx2kL2(Ω),andconditions(7.3),and(7.4)aretrue},W*(Ω)={g(x,t):gCx,t2k,0(Ω¯),2k+1gx2k+1L2(Ω)C(Ω),2lg(0,t)x2l=2lg(p,t)x2l=0,l=0,1,,k}.We define the operator L* mapping the domain V*(Ω) into C(Ω) by (7.2). Let L*¯ be

Acknowledgments

The author is grateful to Professor Shavkat Alimov for his insightful suggestions.

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